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solong [7]
3 years ago
15

The Carson family's pancake recipe uses 2 teaspoons of baking powder for every 1/3 of a teaspoon of salt. How much baking powder

would they need if they used 1 teaspoon of salt?
Physics
2 answers:
melomori [17]3 years ago
5 0

Answer:

6 teaspoons of baking powder required.

Explanation:

Given that

According to the recipe of pancake,

For every \frac{1}{3} teaspoon of salt, 2 teaspoons of baking baking powder is required.

To find:

How much baking powder will be needed, if 1 teaspoon of salt was used ?

Solution:

This problem can be solved using ratio.

\frac{1}3 teaspoon of salt : 2 teaspoons of baking powder

Let us multiply the above ratio with 3.

\frac{1}{3}\times 3 teaspoon of salt : 2 \times 3 teaspoons of baking powder

OR

1 teaspoon of salt : 6 teaspoons of baking powder

So, answer is <em>6 teaspoons </em>of baking powder required.

Also, we can use the unitary method:

\frac{1}3 teaspoon of salt needs =  2 teaspoons of baking powder

1  teaspoon of salt needs =  \frac{2}{\frac{1}3} teaspoons of baking powder

1  teaspoon of salt needs = 2 \times 3 = <em>6</em>  teaspoons of baking powder needed

So, the answer is:

<em>6 teaspoons of baking powder </em>required.

gtnhenbr [62]3 years ago
4 0

Answer:

6 teaspoons of baking powder

Explanation:

This is a simple ratio question.

Every 1/3 of a teaspoon of salt requires 2 teaspoons of baking powder.

Therefore, 1 teaspoon of salt will require:

                               =  1 x 2/1/3

                                    = 2 x 3 = 6 teaspoons of baking powder

<em>Hence, </em><em>6 teaspoons of baking powder</em><em> would be needed if they had used 1 teaspoon of salt.</em>

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A student evaluates a weight loss program by calculating the number of times he would need to climb a 14.0 m high flight of step
Liula [17]

Answer:

400 trips

Explanation:

Mechanical energy needed to climb 14 m by a man of 68 kg

= mgh

= 68 x 9.8 x 14

= 9330 J

1 Kg of fat releases 3.77 x 10⁷ J of energy

.45 kg of fat releases 1.6965 x 10⁷ J of energy

22% is converted into mechanical energy

so 22% of 1.6965 x 10⁷ J

= 3732.3 x 10³ J of mechanical energy will be available for mechanical work.

one trip of climbing of 14 m requires 9330 J of mechanical energy

no of such trip possible with given mechanical energy

= 3732.3 x 10³ / 9330

= 400 trips

7 0
3 years ago
Name two possible ways in wivh fossils can be dated and define them <br>​
Vikentia [17]

Answer:

There are two main methods determining a fossils age, relative dating and absolute dating. Relative dating is used to determine a fossils approximate age by comparing it to similar rocks and fossils of known ages.

Mark me with a crown

6 0
3 years ago
Read 2 more answers
Which of the following is true of children with chronic illness? a.) They are all eligible to recievie special education service
ss7ja [257]

Answer:

c.) Their eligibility for social education services depends on whether their conditions adversely affect their educational functioning.

Explanation:

Chronic Illness is a human health condition in which a particular (or number of) illness is persistent in the body and the effects on the body are long-lasting and are often resistant to treatment. The word chronic is usually used when the disease/illness/sickness and its effects stay in the body for more than three months.

The likeliest answer from the options given is option C because before social education services are given, it has to be decided if their health condition adversely affects their education.

5 0
3 years ago
Suppose you have a 0.750-kg object on a horizontal surface connected to a spring that has a force constant of 150 N/m. There is
marshall27 [118]

Answer:

x=0.0049\ m= 4.9\ mm

d=0.01153\ m=11.53\ mm

Explanation:

Given:

  • mass of the object, m=0.75\ kg
  • elastic constant of the connected spring, k=150\ N.m^{-1}
  • coefficient of static friction between the object and the surface, \mu_s=0.1

(a)

Let x be the maximum distance of stretch without moving the mass.

<em>The spring can be stretched up to the limiting frictional force 'f' till the body is stationary.</em>

f=k.x

\mu_s.N=k.x

where:

N = m.g = the normal reaction force acting on the body under steady state.

0.1\times (9.8\times 0.75)=150\times x

x=0.0049\ m= 4.9\ mm

(b)

Now, according to the question:

  • Amplitude of oscillation, A= 0.0098\ m
  • coefficient of kinetic friction between the object and the surface, \mu_k=0.085

Let d be the total distance the object travels before stopping.

<em>Now, the energy stored in the spring due to vibration of amplitude:</em>

U=\frac{1}{2} k.A^2

<u><em>This energy will be equal to the work done by the kinetic friction to stop it.</em></u>

U=F_k.d

\frac{1}{2} k.A^2=\mu_k.N.d

0.5\times 150\times 0.0098^2=0.0850 \times 0.75\times 9.8\times d

d=0.01153\ m=11.53\ mm

<em>is the total distance does it travel before stopping.</em>

7 0
3 years ago
Calculate the amount of charge necessary to exert a force of 35 N in an electric field of 300 N/C.
densk [106]

Answer:

The amount of charge is "0.117 C" i.e., option A.

Explanation:

The given values are:

Force,

\vec{F} = 35 N

Electric field,

\vec{E} = 300 N/C

Charge,

q = ?

As we know,

⇒  \vec{F}=q\vec{E}

On substituting the given values in the above formula, we get

⇒  35=q\times 300

⇒   q=\frac{35}{300}

⇒   q=0.117 \ C

3 0
3 years ago
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