Answer:
PART A 1st order in A and 0th order in B
Part B The reaction rate increases
Explanation:
<u>PART A
</u>
The rate law of the arbitrary chemical reaction is given by
![-r_A=k\times\left[A\right]^\alpha\times\left[B\right]^\beta\bigm](https://tex.z-dn.net/?f=-r_A%3Dk%5Ctimes%5Cleft%5BA%5Cright%5D%5E%5Calpha%5Ctimes%5Cleft%5BB%5Cright%5D%5E%5Cbeta%5Cbigm)
Replacing for the data
Expression 1 
Expression 2 
Expression 3 
Making the quotient between the fist two expressions

Then the expression for 

Doing the same between the expressions 1 and 3

Then

This means that the reaction is 1st order respect to A and 0th order respect to B
.
<u>PART B
</u>
By the molecular kinetics theory, if an increment in the temperature occurs, the molecules will have greater kinetic energy and, consequently, will move faster. Thus, the possibility of colliding with another molecule increases. These collisions are necessary for the reaction. Therefore, an increase in temperature necessarily produces an increase in the reaction rate.
Hi,
The answer is +2, since there are 10 positive charges (protons) and 8 negative charges (electrons), so 10(+1) + 8(-1)= +10 -8= +2.
If my answer was not clear enough or you’d like further explanation please let me know.
Hope this helps!
The amount of heat needed to melt 423 g of water at 0°C is 141282 J
The heat required to melt water can be obtained by using the following formula:
<h3>Q = mL </h3>
Q is the heat required.
L is the latent heat of fusion (334 J/g)
m is the mass.
With the above formula, we can obtain the heat required to melt the water as illustrated below:
Mass of water (m) = 423 g
Latent heat of fusion (L) = 334 J/g
<h3>Heat (Q) required =? </h3>
Q = mL
Q = 423 × 334
<h3>Q = 141282 J</h3>
Therefore, the amount of heat needed to melt 423 g of water at 0°C is 141282 J
Learn more: brainly.com/question/17084080

Thus 174 protons would make at most 6 copper atoms. However, it would take 174 extra electrons (29 per atom) and even more neutrons than that to construct neutral copper atoms with stable nuclei.
The answer to this question is 6.25ml
To answer this question, you need to calculate the azithromycin drug doses for this patient. The calculation would be: 25kg * 10mg/kg/d= 250mg/d
Then multiply the doses with the available drug. It would be:
250 mg/d / (200mg/5ml)= 6.25ml/d