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NeTakaya
4 years ago
11

If you were to push a pile of books across a table, in which location would this be the easiest?

Physics
1 answer:
kati45 [8]4 years ago
6 0

same amount is the answer

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Si tomamos como referencia el recipiente uno y se aplican 5 gramos de tinta y el agua se moviera a una velocidad de 10m/s cual s
tigry1 [53]

Answer:

Kinetic energy = 0.25 J

Explanation:

The question is "If we take container one as a reference and apply 5 grams of ink and the water moves at a speed of 10m / s, what would the kinetic energy of the solution be?"

We have,

Mass of ink, m = 5 grams = 0.005 kg

Speed of water, v = 10 m/s

We need to find the kinetic energy of the solution of water and ink. Kinetic energy is associated with the motion of an object. Its formula is given by :

K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 0.005\times (10)^2\\\\K=0.25\ J

So, the kinetic energy of the solution is 0.25 Joules.

5 0
4 years ago
What is the maximum centripetal acceleration experienced by a person standing still on the surface of the Earth? Where must they
skelet666 [1.2K]

Answer:

The person must be located in the Equator Line. The maximum centripetal acceleration experienced by a person is 0.0337 meters per square second.

Explanation:

Physically speaking, the centripetal acceleration (a_{r}), measured in meters per square second, experienced by a person is defined by the following expression:

a_{r} = \omega^{2}\cdot r (1)

Where:

\omega - Angular speed of the Earth, measured in radians per second.

r - Distance perpendicular to the rotation axis, measured in meters.

Since rotation axis passes through poles and distance described above is directly proportional to centripetal acceleration. The person must be located in the Equator Line, which is equivalent to the radius of the planet.

In addition, the angular speed of the Earth can be calculated in terms of its period (T), measured in seconds:

\omega = \frac{2\pi}{T} (2)

If we know that r = 6.371\times 10^{6}\,m and T = 86400\,s, then the maximum centripetal acceleration experienced by a person is:

a_{r} = \left(\frac{2\pi}{86400\,s} \right)^{2}\cdot (6.371\times 10^{6}\,m)

a_{r} = 0.0337\,\frac{m}{s^{2}}

The maximum centripetal acceleration experienced by a person is 0.0337 meters per square second.

6 0
3 years ago
The breaker of a certain circuit installed in a house shuts down at 10 amps. Can we connect a water heat of 2 kW to a power outl
dangina [55]
P = VI => I = P/V = 2000/240 = 8.33A  < 10A    so yes we can
5 0
3 years ago
g The human ear can perceive sounds with frequencies ranging from 20.0 Hz to 20000 Hz. If the speed of sound is 330 m/s in air a
garri49 [273]

Answer:  lamda max= 16,5m   lamda min=  0,0165m (air)  

lamda  max= 75m, lamda min=0,075m (water)

Explanatin

7 0
3 years ago
Choose one thing in each label to identify the parts of DNA
laila [671]
It would be B because it makes science to the topic
8 0
3 years ago
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