To solve this problem we will apply the concepts related to equilibrium, for this specific case, through the sum of torques.

If the distance in which the 600lb are applied is 6in, we will have to add the unknown Force sum, at a distance of 27in - 6in will be equivalent to that required to move the object. So,



So, Force that must be applied at the long end in order to lift a 600lb object to the short end is 171.42lb
On behalf of the state, write an invitation for the siblings for the gala dinner
Hello there, we would like to welcome you to the gala dinner hope you can come :)
.........,....,,,???........
Answer:

Explanation:
From the question we are told that

Generally the equation for momentum is mathematically given by

Therefore
T-Joe momentum 

