What are the three subatomic particles of an atom?

Physics

2 answers:

ZanzabumX [31]3 years ago

8 0

Proton, neutron, and electron. The proton is positive, the neutron is neutral, and the election is negative.

Anestetic [448]3 years ago

5 0

Protons, neutrons, and electrons are the three main subatomic particles found in an atom. Protons have apositive (+) charge. An easy way to remember this is to remember that both proton and positive start with theletter "P." Neutrons have no electrical charge.

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you find out that it takes 2 sec. for the swing to complete one cycle. what is the swing`s period and frequency?

Gnesinka [82]

The time it takes "to complete one cycle" is a perfect definition for period.
So the 2 sec that you measured is the swing's period.

Frequency is just 1/period (the 'reciprocal' of the period).
For this swing, the frequency is 1/(2sec) = 0.5 per second = 0.5 Hz.

( "Hertz" means "per second")

6 0

3 years ago

A 2020 kg car traveling at 14.2 m/s collides with a 2940 kg car that is initally at rest at a stoplight. The cars stick together

velikii [3]

Answer:

The answer is 3,064x $e^{-4}$

Explanation:

When the collision happens, the momentum of the first car is applied to the both of them.

So we can calculate the force that acts on both cars as:

The momentum of the first car is P = 2020 kg x 14.2 m/s = 28,684 kg.m/s
The acceleration of both cars after the crash is going to be a = P / mtotal which will give us a = 28,684 / (2020+2940) = 5.78 m/s
Since the second car was initially not moving, the final acceleration was calculated with the momentum of the first car.

Now we can find the force that acts on both of them by using the formula F = m.a which will give us the result as:

F = (2020+2940) x 5.78 = 28,684

The friction force acts in the opposite direction and if they stop after moving 2.12 meters;

Friction force is Ff = μ x N where μ is the friction coefficient and the N is the normal force which is (2020+2940) x 10 if we take gravitational force as 10, equals to 49,600.
F - Ffriction = m x V
28,684 - μ x 49,600 = 4960 x 5.78
μ = 3,064x $e^{-4}$

4 0

3 years ago

What is the momentum of an object weighing 7.5 kg moving at 1.6 m/s?

AleksAgata [21]

Answer:

$momentum = mass \times velocity \\ = 7.5 \times 1.6 \\ = 12 \: kg {ms}^{ - 1}$