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3 years ago

If a 1200kg car travels 20 m/s and slows down for a stop, what is its momentum?

Physics

1 answer:

frosja888 [35]3 years ago

3 0

Answer:

24000kgm/s

Explanation:

Given parameters:

Mass of car = 1200kg

Velocity = 20m/s

Unknown:

Momentum = ?

Solution:

Momentum is the amount of motion a body possesses.

Momentum = mass x velocity

Now insert the parameters and solve;

Momentum = 1200 x 20 = 24000kgm/s

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Skater 1 has a mass of 45 kg and is at rest. Skater 2 has a mass of 50 kg and is moving slowly at a constant velocity of 3.2 m/s

algol13

Answer:

None

Explanation:

Force, F is given by ma where m is the mass of an object and a is acceleration

Acceleration is the rate of change in velocity per unit time. Since skaters with mass of 75 kg and 50 kg are moving at a constant speed, there is no acceleration hence F=50*0=0 and F=75*0=0

For skater of 45 kg, he is at rest to mean the initial and final velocitu of the skater is zero hence no acceleration, the force will be 45*0=0

Therefore, none of the skaters will experience a greater net force.

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3 years ago

Archerfish are tropical fish that hunt by shooting drops of water from their mouths at insects above the waterÂs surface to knoc

sergij07 [2.7K]

Answer:

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Explanation:

Take the mass of the fish and divide it by the mass of the water:

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Divide the given speed by the value we found above:

2.5/216.667=.0115

Answer can be rounded up to .012

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3 years ago

Read 2 more answers

Suppose you have a total charge qtot that you can split in any manner. Once split, the separation distance is fixed. How do you

dybincka [34]

Answer:

Answer is explained in the explanation section below.

Explanation:

Solution:

We know from the Coulomb's Law that, Coulomb's force is directly proportional to the product of two charges q1 and q2 and inversely proportional to the square of the radius between them.

So,

F = $\frac{Kq1q2}{r^{2} }$

Now, we are asked to get the greatest force. So, in order to do that, product of the charges must be greatest because the force and product of charges are directly proportional.

Let's suppose, q1 = q

So,

if q1 = q

then

q2 = Q-q

Product of Charges = q1 x q2

Now, it is:

Product of Charges = q x (Q-q)

So,

Product of Charges = qQ - $q^{2}$

And the expression qQ - $q^{2}$ is clearly a quadratic expression. And clearly its roots are 0 and Q.

So, the highest value of the quadratic equation will be surely at mid-point between the two roots 0 and Q.

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3 years ago

A cannon ball is shot straight upward with a velocity of 72.50 m/s. How high is the cannon ball above the ground 3.30 seconds af

disa [49]

Answer:

Explanation:

Given

Cannon is fired with a velocity of $u=72.50\ m/s$

Using Equation of motion

$y=ut+\frac{1}{2}at^2$

where

$y=displacement$

$u=initial\ velocity$

$a=acceleration$

$t=time$

after time $t=3.3 s$

$y=72.50\times 3.3-\frac{1}{2}\times 9.8\times (3.3)^2$

$y=239.25-53.36$

$y=185.89\ m$

So after 3.3 s cannon ball is at a height of 185.89 m

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3 years ago

True or false? the potential energy of a membrane potential comes solely from the difference in electrical charge across the mem

bazaltina [42]

The statement would be False. T<span>he potential energy of a membrane potential comes solely from the difference in electrical charge across the membrane. In addition to that, membrane potential actually regulates the potential difference of nerve cells across the membrane estimated at 70 mV.</span>

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4 years ago

If a 1200kg car travels 20 m/s and slows down for a stop, what is its momentum?​

If a 1200kg car travels 20 m/s and slows down for a stop, what is its momentum?