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inysia [295]
3 years ago
5

Answer fast !!!!!!! pleaseee

Physics
2 answers:
Svetllana [295]3 years ago
8 0
Magnetic fields

it’s the only answer that goes with the question
wariber [46]3 years ago
5 0

Answer: Magnetic Fields

Explanation:

ig

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What is the magnitude of the impulse that would cause the 2-kg box to accelerate from 2 m/s to 5 m/s?
Law Incorporation [45]

6 J is the impulse caused by the change in velocity of 2 kg box from 2 m/s to 5 m/s.

Answer:

The magnitude of impulse is 6 J.

Explanation:

Impulse is the force acting on any object for a given time interval. As force is equal to the product of mass and acceleration and acceleration is the rate of change of velocity with time. Then the product of force with time interval will be equal to the product of mass with change in velocity.

F = m a = \frac{m(v-u)}{(t_{2}-t_{1}  )}

FΔt = mΔv

Impulse = FΔt=mΔv

As the mass of box is given as 2 kg and the velocity changes from 2 m/s to 5 m/s, then the impulse = 2 × (5-2) = 2 ×3 =6 J

So 6 J is the impulse caused by the change in velocity of 2 kg box from 2 m/s to 5 m/s.

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3 years ago
A snake slithered across the sidewalk in between two sign posts. At the first sign post his speed was
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This is an example of Uniform Speed

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Uniform Speed => no change in speed

Uniform Accelerations Speed => There is a change in speed, but the acceleration remains the same.

#LearnWithEXO

5 0
3 years ago
If an object starts from rest, what is its initial velocity?
Vladimir79 [104]

Answer:

0 m/s

Explanation:

velocity= change in displacement/ time

at rest, the ball does not travel any distance

0/ t

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4 0
4 years ago
What is one standard kilogramun si system<br><br><br><br><br>​
Phoenix [80]

Answer:

The kilogram (kg) is defined by taking the fixed numerical value of the Planck constant h to be 6.62607015 ×10−34 when expressed in the unit J s, which is equal to kg m2 s−1, where the meter and the second are defined in terms of c and ∆νCs.

3 0
3 years ago
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If the distance between two masses is tripled, the gravitational force between changes by a factor of
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A. 1/9

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The gravitational force between two objects is given by

F=G\frac{m_1 m_2}{r^2}

where

G is the gravitational constant

m1 and m2 are the two masses

r is the distance between the two masses

From the formula, we see that the magnitude of the force is inversely proportional to the square of the distance: therefore, if the distance is tripled (increased by a factor 3), the magnitude of the force changes by a factor

\frac{1}{r^2}=\frac{1}{3^2}=\frac{1}{9}

6 0
4 years ago
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