Ask question

Ask question

All categories

2 years ago

8

Which scientific method could I use to test this hypothesis? "If the mass and the volume of an object are known, then its densit

y can be calculated dividing the object's mass by its volume."

2 answers:

Varvara68 [4.7K]2 years ago

7 0

Answer:

To test the hypothesis, we need to make an observation or perform an experiment associated with the prediction. For instance, in this case, we would plug the toaster into a different outlet and see if it toasts.

inspired by answer up there

sorry i couldn't add details because think its bad

Hypothesis testing is a formal procedure for investigating our ideas about the world using statistics. It is most often used by scientists to test specific predictions, called hypotheses, that arise from theories.

REY [17]2 years ago

3 0

Answer:

Multiple so you can test multiple hypothesis at once

Explanation:

because

You might be interested in

A student believes a metal rod will gain a negative static charge when

Dennis_Churaev [7]

Answer:

no, when a plastic rod is rubbed with a duster, electrons are transferred from one material to the other. The material that gains electrons becomes negatively charged. The material that loses electrons becomes positively charged.

Explanation:

3 0

3 years ago

imagine that 501 people are present in a movie theater of volume 8.00 x10^3 that is sealed shut so no air can escape. Each perso

Semenov [28]

Answer:

The temperature of air will increase by $\Delta T=41044.967\ K$

Explanation:

Given:

no. of person in a theater, $n=501$

volume of air in the theater, $V=8\times 10^3\ m^3$

rate of heat given off by each person, $P=110\ J.s^{-1}$

duration of movie, $t=2\ hr=7200\ s$

initial pressure in the theater, $p_i=1.01\times 10^5\ Pa$

initial temperature in the theater, $T_i=20+273=293\ K$

specific heat capacity of air at the given conditions, $c=1.0061\ J.kg^{-1}.K^{-1}$

<u>The total quantity of heat released by the total people in the theater during the movie:</u>

$Q=n.P.t$

$Q=501\times 110\times 7200$

$Q=396792000\ J$

<u>Form the relation of heat capacity:</u>

$Q=m.c.\Delta T$

∵ $p_i.V=m.R.T$

$Q=(\frac{p_i.V}{R.T}) \times c\times (T_f-T_i)$

$396792000=(\frac{1.01\times 10^5\times 8\times 10^3}{287\times 293}) \times 1.0061\times (T_f-293)$

$T_f=41337.967\ K$

Change in temperature of air:

$\Delta T=41044.967\ K$

8 0

3 years ago

You have a 100 g sample of Unobtainium, it is half a life of 2 years. How much will be left after 10 years?

sergeinik [125]

3.125 ,, that is the answer !!

3 0

3 years ago

When the resistance in a circuit remains constant, how are the voltage and current related?

solmaris [256]

V=IR, therefore when resistance is constant the voltage and current are directly proportional

6 0

4 years ago

Read 2 more answers

A total charge of Q coulomb is uniformly distributed along a rod 40cm in length.find find the electric field intensity 20cm away

Tatiana [17]

For a total charge of Q coulomb is uniformly distributed along a rod 40cm in length, the electric field intensity 20cm away from the rod is mathematically given as

E1=1.598*10^11v/m

<h3>What is the electric field intensity 20cm away from the rod along its perpendicular bisector?</h3>

Generally, the equation for the initial electric field intensity is mathematically given as

$dEp=\int{kd/r}cosd\theta$

Therefore

$e1=kd/r{sin\theta2+sinR1}$

Hence

$E1=(9*10^9/20*10^{-2})({sin45+sin45})*B/40*10^-2$

E1=B*9*10^{13})/(10*110)* $\sqrt{2}$

E1=1.598*10^11v/m

In conclusion, the electric field intensity

E1=1.598*10^11v/m

Read more about Electric field

brainly.com/question/9383604

6 0

2 years ago