Complete Question
Use Stefan's law to find the intensity of the cosmic background radiation emitted by the fireball of the Big Bang at a temperature of 2.81 K. Remember that Stefan's Law gives the Power (Watts) and Intensity is Power per unit Area (W/m2).
Answer:
The intensity is 
Explanation:
From the question we are told that
The temperature is 
Now According to Stefan's law
Where 
is the Stefan Boltzmann constant with value 
Now the intensity of the cosmic background radiation emitted according to the unit from the question is mathematically evaluated as
=> 
=> 
substituting values
We are asked in this problem to determine the power wasted given the two voltages: 50,000 and 12,000 volts. By physics, the formula to determine power using volts is expressed as P = VI where P is in watts, V is in volts and I, current, is in Amperes. In this case, we just have to plug the given data to the equation named.
1) P1 = 50,000*I
2) P2 = 12,000 * I
P1 - P2 = (50,000-12,000)*I
ΔP = 48,000 I
So the power wasted then is equal to 48,000 times the current employed to achieve power. I should be specified as well to determine the exact difference.
To throw stuff. Like in the old'n days they used them to destroy castles.
Answer:
The drift speed of the electrons in the wire is 2.12x10⁻⁴ m/s.
Explanation:
We can find the drift speed by using the following equation:
Where:
I: is the current = 4.50 A
n: is the number of electrons
q: is the modulus of the electron's charge = 1.6x10⁻¹⁹ C
A: is the cross-sectional area = 2.20x10⁻⁶ m²
We need to find the number of electrons:
Now, we can find the drift speed:
Therefore, the drift speed of the electrons in the wire is 2.12x10⁻⁴ m/s.
I hope it helps you!
