The answer is
A the ants climbed up the table
Answer:
removing the methanol as it is formed
Explanation:
One of the ways to drive the equilibrium position towards the right is to remove one of the products formed.
According to Me Chatelier's principle, the imposition of a constraint on a system in a equilibrium causes the equilibrium position to shift towards a new position that annuls the constraint. Hence, removing the methanol causes the equilibrium position to shift to the far right in order to reestablish equilibrium according to Le Chatelier's principle.
Answer:
The correct option is: (D) would function as both an acid and a base
Explanation:
A carbon skeleton bonded to a amino group as well as a carboxyl group, will behave as an acid in basic medium and base in acidic medium. This is because the carboxyl group present in the compound will release a proton in basic medium and the amino group will accept a proton in the acidic medium.
<u>Therefore, a carbon skeleton which is covalently bonded to a carboxyl and amino group will behave as both acid and base.</u>
I’m not sure if there was important information in the question before this one, but the answer based on the info I have is B.
The density of water is 1kg/L. Since the density of the block is less, it will float.
