The vertical velocity of the projectile upon returning to its original is 17. 74 m/s
<h3>
How to determine the vertical velocity</h3>
Using the formula:
Vertical velocity component , Vy = V * sin(α)
Where
V = initial velocity = 36. 6 m/s
α = angle of projectile = 29°
Substitute into the formula
Vy = 36. 6 * sin ( 29°)
Vy = 36. 6 * 0. 4848
Vy = 17. 74 m/s
Thus, the vertical velocity of the projectile upon returning to its original is 17. 74 m/s
Learn more about vertical velocity here:
brainly.com/question/24949996
#SPJ1
Assume that the small-massed particle is and the heavier mass particle is .
Now, by momentum conservation and energy conservation:
Now, there are 2 solutions but, one of them is useless to this question's main point so I excluded that point. Ask me in the comments if you want the excluded solution too.
So now, we see that and . So therefore, the smaller mass recoils out.
Hope this helps you!
Bye!
Answer:
71.85 m/s
Explanation:
Given the following :
Length of skid marks left by jaguar (s) = 290 m
Skidding Acceleration (a) = - 8.90m/s²
Final velocity of jaguar (v) = 0
Speed of Jaguar before it Began to skid =?
Hence, initial speed of jaguar could be obtained using the formula :
v² = u² + 2as
Where
v = final speed of jaguar ; u = initial speed of jaguar(before it Began to skid) ; a = acceleration of jaguar ; s = distance /length of skid marks left by jaguar
0² = u² + (2 × (-8.90) × 290)
0 = u² + (-5,162)
u² = 5162
Take the square root of both sides
u = √5162
u = 71.847 m/s
u = 71.85m/s
Answer:
0.24 ? I hope that was the answer you were looking for.
Explanation:
Answer:
option D
Explanation:
given.
horizontal velocity of arrow and a ball given as 50 m/s and 44 m/s respectively from the top of a building over flat ground.
In vertical direction, they are both identical
In vertical direction the initial velocity of arrow and a ball is 0 m/s
Their acceleration due to gravity is same for both arrow and a ball 9.8 m/s²
they will react bottom at the same time
time of flight is same for both
now,
In horizontal direction,
distance = speed × time
Since speed is more for arrow, it will travel more horizontal distance at the same time.
the correct answer is option D