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Gnom [1K]
3 years ago
14

You go and choose a solid chemical rocket which expels gas from the engine at 3 kilometers per second. The rocket has a total ma

ss of 2 kg with the fuel being 1 kg. The theoretical maximum speed of this rocket is:
Physics
1 answer:
N76 [4]3 years ago
5 0

Answer:

1500 m/s

Explanation:

From Newton's Third law of motion,

Momentum of the hot gas = Momentum of the  rocket

mv = MV............................... Equation 1

Where m = mass of the fuel, v = velocity of the gas, M = mass of the rocket, V = velocity of the rocket.

Making V the subject of the equation

V = mv/M......................... Equation 2

Given: m = 1 kg, M = 2 kg, v = 3 km/s.

Substituting into equation 2

V = 1(3)/2

V = 3/2

V = 1.5 km/s

V = 1500 m/s

Hence the maximum speed of the rocket = 1500 m/s

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The water stream strikes the inclined surface of the cart. Determine the power produced by the stream if, due to rolling frictio
levacccp [35]

Answer

given,

constant speed of cart on right side = 2 m/s

diameter of nozzle = 50 mm = 0.05 m

discharge flow through nozzle = 0.04 m³

One-fourth of the discharge flows down the incline

three-fourths flows up the incline

Power = ?

Normal force i.e. Fn acting on the cart

F_n = \rho A (v - u)^2 sin \theta

v is the velocity of jet

Q = A V

v = \dfrac{0.04}{\dfrac{\pi}{4}d^2}

v= \dfrac{0.04}{\dfrac{\pi}{4}\times 0.05^2}

v = 20.37 m/s

u be the speed of cart assuming it to be u = 2 m/s

angle angle of inclination be 60°

now,

F_n = 1000 \times \dfrac{\pi}{4}\times 0.05^2\times (20.37 - 2)^2 sin 60^0

F n = 2295 N

now force along x direction

F_x = F_n sin 60^0

F_x = 2295 \times sin 60^0

F_x = 1987.52\ N

Power of the cart

P = F x v

P = 1987.52 x 20.37

P = 40485 watt

P = 40.5 kW

3 0
4 years ago
A 1.5 kilogram cart initially moves at 2.0 meters per second. It is brought to rest by a constant net forcé in 3.0 second. What
lubasha [3.4K]

The net force on the cart is

                   Force = (mass) x (acceleration) .

We know the mass = 1.5 kilogram, but we need to
calculate the acceleration.

               Acceleration = (change in speed) / (time for the change)

Change in speed = (ending speed) minus (beginning speed)

                               =    ( 0 )  -  ( 2 m/s )  =   -2 m/s

Acceleration =  (change in speed) / (time for the change)

                       =       ( -2 m/s )   /   (3 sec)

                       =           - 2/3  m/s² .

Finally ...        Net force = (mass) x (acceleration)

                                       =  (1.5 kilogram) x ( - 2/3 m/s²)

                                       =  ( - 3/2 x 2/3 )  (kg-m/s²)

                                       =       - 1  newton .

The negative sign on the force means the force is applied
opposite to the direction the cart is moving.  That gives
negative acceleration (slowing down), and the cart
eventually stops.   

3 0
4 years ago
What are the similarities between mountains, plateaus, and plains?
tiny-mole [99]
They are all elevated land forms.
3 0
3 years ago
Read 2 more answers
A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 3.60 m/s. The car is a distan
In-s [12.5K]

Answer:

101 meters

Explanation:

Distance traveled by the tourist:

d = 3.60 m/s × t

Distance traveled by the bear:

d + 39.3 m = 5.00 m/s × t

Substitute:

3.6 t + 39.3 = 5 t

39.3 = 1.4 t

t = 28.1

d = 101

7 0
3 years ago
A well-insulated turbine operating at steady state develops 23 mw of power for a steam flow rate of 40 kg/s. the steam enters at
Lena [83]
You have to use the steady state of forms and, mass and energy balances in order to know the pressure of the inlet. m1 = m2 = m. Solve for the assumptions of steam flow rate, as well as the saturated vapor. Just simplify it. 
3 0
3 years ago
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