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Gnom [1K]
3 years ago
14

You go and choose a solid chemical rocket which expels gas from the engine at 3 kilometers per second. The rocket has a total ma

ss of 2 kg with the fuel being 1 kg. The theoretical maximum speed of this rocket is:
Physics
1 answer:
N76 [4]3 years ago
5 0

Answer:

1500 m/s

Explanation:

From Newton's Third law of motion,

Momentum of the hot gas = Momentum of the  rocket

mv = MV............................... Equation 1

Where m = mass of the fuel, v = velocity of the gas, M = mass of the rocket, V = velocity of the rocket.

Making V the subject of the equation

V = mv/M......................... Equation 2

Given: m = 1 kg, M = 2 kg, v = 3 km/s.

Substituting into equation 2

V = 1(3)/2

V = 3/2

V = 1.5 km/s

V = 1500 m/s

Hence the maximum speed of the rocket = 1500 m/s

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4. Shirley Bored sits in her seat in the English classroom. The force of gravity on Earth pulls
Sedbober [7]

Answer:

600 N upward

Explanation:

According to Newton's third law, for every action their is an equal and opposite reaction. The equal and opposite reaction to a downward force of magnitude 600 N is an upward force of magnitude 600 N

4 0
3 years ago
What is the frequency of infrared light of 1.0 x 10-4 m wavelength?
dedylja [7]
Speed of light= wavelenght * frequency

Frequency = (3x10^8)/(1 x 10^-4)
= 3 x 10^+12
5 0
3 years ago
A stationary speed gun emits a microwave beam at 2.10*10^10Hz. It reflects off a car and returns 1030 Hz higher. What is the spe
KIM [24]

Answer: V = 15 m/s

Explanation:

As  stationary speed gun emits a microwave beam at 2.10*10^10Hz. It reflects off a car and returns 1030 Hz higher. The observed frequency the car will be experiencing will be addition of the two frequency. That is,

F = 2.1 × 10^10 + 1030 = 2.100000103×10^10Hz

Using doppler effect formula

F = C/ ( C - V) × f

Where

F = observed frequency

f = source frequency

C = speed of light = 3×10^8

V = speed of the car

Substitute all the parameters into the formula

2.100000103×10^10 = 3×10^8/(3×10^8 -V) × 2.1×10^10

2.100000103×10^10/2.1×10^10 = 3×108/(3×10^8 - V)

1.000000049 = 3×10^8/(3×10^8 - V)

Cross multiply

300000014.7 - 1.000000049V = 3×10^8

Collect the like terms

1.000000049V = 14.71429

Make V the subject of formula

V = 14.71429/1.000000049

V = 14.7 m/s

The speed of the car is 15 m/s approximately.

8 0
3 years ago
A particle with charge 6 mC moving in a region where only electric forces act on it has a kinetic energy of 1.9000000000000001 J
Vesna [10]

Answer:

16.9000000000000001 J

Explanation:

From the given information:

Let the initial kinetic energy from point A be K_A = 1.9000000000000001 J

and the final kinetic energy from point B be K_B = ???

The charge particle Q = 6 mC = 6 × 10⁻³ C

The change in the electric potential from point B to A;

i.e. V_B - V_A = -2.5 × 10³ V

According to the work-energy theorem:

-Q × ΔV = ΔK

-Q \times ( V_B - V_A) = (K_B - K_A)

-(6\times 10^{-3}\ C) \times ( -2.5 \times 10^3) = (K_B - 1.9000000000000001 \ J)

15 = (K_B - 1.9000000000000001 \ J)

K_B = 15+ 1.9000000000000001 \ J

\mathbf{K_B =1 6.9000000000000001 \ J}

3 0
3 years ago
Aaron created the chart to list the benefits and limitations of using synthetic polymers . In which row has Aaron made an error
Sever21 [200]

Answer:

Its B trust me

8 0
3 years ago
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