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Helen [10]
2 years ago
13

1. Ethanol and 2,6-dimethylphenol both have hydroxyl groups that can be deprotonated by a base. Why does ethanol act as a solven

t but not as a nucleophile under the conditions used in this experiment
Chemistry
1 answer:
Volgvan2 years ago
3 0

Anions are solvated in protic hydrogen-bonding solvents (such as ethanol). Consequently, nucleophiles are less reactive. Since soft nucleophiles are less strongly solvated than hard nucleophiles, these solvents boost the relative reactivity of soft anions.

<h3>Ethanol is either a nucleophile or a base.</h3>

The ethanol is a base  Because carbocation is an extremely reactive species, a base or nucleophile as weak as ethanol can replace or remove it. SN1 and E1 would not be conceivable without the carbocation or a strong departing group.

<h3>How do solvents impact anionic nucleophile's reactivity?</h3>

In polar aprotic solvents, nucleophilic substitution reactions of anionic nucleophiles often proceed more quickly. The normal relative reactivity order in such solvents (like DMSO)is Anions are solvated in protic hydrogen-bonding solvents (such as ethanol). Consequently, nucleophiles are less reactive.

Learn more about nucleophiles here:-

brainly.com/question/27127109

#SPJ4

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Plz help with this........​
Elodia [21]
<h2>GREETINGS!</h2><h2>_____________________________________</h2><h3>Answer:</h3>

ITS C_{4}H_{10} AND C_{5}H_{12}

<h2>_____________________________________</h2><h3><u>GENERAL FORMULA OF ALKANE</u></h3><h3>                    C_{n}H_{2n+2}</h3>

Where n is the number of CARBONS

<h2>_____________________________________</h2>

A)

By using the General Formula of Alkanes having 4 carbon atoms is

                        C_{4}H_{2x4+2}

                        C_{4}H_{10}

C)

By using the General Formula of Alkanes having 5 carbon atoms is

                         C_{5}H_{2x5+2}

                         C_{5}H_{12}

<h2>_____________________________________</h2>

IF YOU USE THE SAME FORMULA FOR THE OTHER TWO OPTIONS THE OUTCOME WILL NOT BE AS SAME AS GIVEN IN THE QUESTION SO THOSE TWO ARE CAN NOT BE OUR ANSWER

<h2>_____________________________________</h2><h2>HOPE THIS HELPS!</h2>

                       

3 0
3 years ago
Some water released 7800 J of energy when cooled from 78°C to 33°C. What was the mass of the water?
Karo-lina-s [1.5K]

Answer:

-41. 47

Explanation:

m = q / Cp x T

m = Mass

q = Energy (or joules)

Cp = Heat Capacity

T = Change in Temperature

Water's heat capacity is always 4.18.

This is the formula you'll need for change in temperature:

Final - Initial

So, 33 - 78 = -45

m = 7800 / 4.18 x -45

= -41.47

4 0
2 years ago
A student visits the beach during a very hot day. She steps on the sand and jumps because it is so hot. What type of heat transf
sammy [17]
Answer is: thermal conductuction.
Thermal conductuction is the transfer of heat<span> through physical contact. </span>Thermal conduction<span> is the transfer of heat</span> by microscopic collisions of particles. <span>Heat spontaneously flows from a hotter to a colder body.
</span>The process of heat conduction depends on four basic factors: the temperature gradient<span>, the cross section of the </span>materials<span> involved, their path length and the properties of those materials.</span>


3 0
4 years ago
Read 2 more answers
The cation of the salt is sodium ion, and the anion is aurothiosulfate ion. Based on the chemical formula of the salt, what must
marta [7]

Answer:

3-

Explanation:

Sodium aurothiosulfate is a salt with the formula Na₃Au(S₂O₃)₂. The cation of the salt is sodium ion, and the anion is aurothiosulfate ion. We can determine the charge of the aurothiosulfate ion, considering that the sum of the positive and negative charges must be equal to the charge of the compound, which is zero.

3 × Na⁺ + 1 × Au(S₂O₃)₂ⁿ⁻ = 0

3 × +1 + 1 × Au(S₂O₃)₂ⁿ⁻ = 0

Au(S₂O₃)₂ⁿ⁻ = 3-

7 0
3 years ago
Which element would release the most energy while adding an electron to a neutral atom in the gas phase?
JulijaS [17]
Answer: bromine

Explanation: Thus bromine would release most energy while adding an an electron to a neutral atom in the gas phase.
5 0
3 years ago
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