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3 years ago

14

Help 12 points yes sir people

2 answers:

aksik [14]3 years ago

5 0

Maybe the first or third ☝️ one

Cerrena [4.2K]3 years ago

3 0

Answer:

glaciers seem like it would make sence

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How many moles of potassium oxide (K2O) will be formed when 1.52 moles of potassium reacts with oxygen according to the followin

Ghella [55]

The balanced chemical reaction is given above however I believe the coefficients are wrong. It should be:

4K + O2 = 2K2O

We use data from that reaction to obtain relationships between substances. We are given the amount of potassium that reacts. We proceed as follows:

1.52 mol K ( 2 mol K2O / 4 mol K ) = 0.76 mol of K2O is formed

6 0

4 years ago

PLZ HELP BEING TIMED!!! PLZ ANSWER!!!!

andreev551 [17]

Answer:its going to be a

Explanation:

4 0

3 years ago

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Convert 1.39 x 10^24 atoms of carbon to moles of carbon

Nimfa-mama [501]

If 1mol ------- is ----------- 6,02×10²³
so x ------- is ----------- 1,39×10²⁴

$x=\frac{1,39*10^{24}*1mol}{6,02*10^{23}}\approx2,31mol$

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3 years ago

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A mouse is placed in a sealed chamber with air at 769.0 torr. This chamber is equipped with enough solid KOH to absorb any CO2 a

svlad2 [7]

<u>Answer:</u> The amount of oxygen gas consumed by mouse is 0.202 grams.

<u>Explanation:</u>

We are given:

Initial pressure of air = 769.0 torr

Final pressure of air = 717.1 torr

Pressure of oxygen = Pressure decreased = Initial pressure - Final pressure = (769.0 - 717.1) torr = 51.9 torr

To calculate the amount of oxygen gas consumed, we use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 51.9 torr

V = Volume of the gas = 2.20 L

T = Temperature of the gas = 292 K

R = Gas constant = $62.364\text{ L. Torr }mol^{-1}K^{-1}$

n = number of moles of oxygen gas = ?

Putting values in above equation, we get:

$51.9torr\times 2.20L=n\times 62.364\text{ L. Torr }mol^{-1}K^{-1}\times 292K\\\\n=\frac{51.9\times 2.20}{62.364\times 292}=0.0063mol$

To calculate the mass from given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of oxygen gas = 0.0063 moles

Molar mass of oxygen gas = 32 g/mol

Putting values in above equation, we get:

$0.0063mol=\frac{\text{Mass of oxygen gas}}{32g/mol}\\\\\text{Mass of oxygen gas}=(0.0063mol\times 32g/mol)=0.202g$

Hence, the amount of oxygen gas consumed by mouse is 0.202 grams.

5 0

3 years ago

The mass of copper obtained experimentally was 0.872 g. Calculate the percentage yield of

frozen [14]

Answer:

% yield = (0.872 g Cu / 1.017 g ) x 100 = 85.74 %.

6 0

3 years ago