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Ludmilka [50]
3 years ago
8

Can anyone explain oxidation, and reduction reactions of:

Chemistry
1 answer:
____ [38]3 years ago
4 0

Answer:

Reduction of Aldehydes and Ketones. Hydride reacts with the carbonyl group, C=O, in aldehydes or ketones to give alcohols. ... Reduction of ketones gives secondary alcohols. The acidic work-up converts an intermediate metal alkoxide salt into the desired alcohol via a simple acid base reaction.

The carbon atom of a carboxyl group is in a relatively high oxidation state. Diborane, B2H6, reduces the carboxyl group in a similar fashion. ... Sodium borohydride, NaBH4, does not reduce carboxylic acids; however, hydrogen gas is liberated and salts of the acid are formed.

Primary alcohols can be oxidized to form aldehydes and carboxylic acids; secondary alcohols can be oxidized to give ketones. Tertiary alcohols, in contrast, cannot be oxidized without breaking the molecule's C–C bonds.

A secondary alcohol can be oxidised into a ketone using acidified potassium dichromate and heating under reflux. The orange-red dichromate ion, Cr2O72−, is reduced to the green Cr3+ ion. This reaction was once used in an alcohol breath test.

hope it will help u

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How many oxygen atoms are present in 23.6 grams of aspartame?
olga55 [171]
The formula of aspartame is <span>C14H18N2O5.
From the periodic table:
molecular mass of hydrogen = 1 grams
molecular mass of carbon = 12 grams
molecular mass of nitrogen = 14 grams
molecular mass of oxygen = 16 grams

This means that:
molar mass of aspartame = 14(12)+18(1)+2(14)+5(16) = 294 grams
Therefore, each 294 grams of aspartame contains 5(16) = 80 grams of oxygen. To know number of grams of oxygen in 23.6 grams of aspartame, simply use cross multiplication as follows:
mass of oxygen = (23.6x80) / 294 = 6.42 grams</span>
7 0
3 years ago
How many moles of carbon dioxide are produced when 22.8g of butane react
Juliette [100K]
Butane undergoes combustion to produce carbon dioxide and water, expressed in the following reaction <span> C4H10 (g) + O2 (g) → 4CO2 (g) + 5H2O (g) . 1 mole of butane is to 4 moles of CO2. In this case, when 22.8 grams of butane or 0.393 moles of it, 69.18 grams of carbon dioxide is produced</span>
4 0
3 years ago
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mote1985 [20]

Answer: C

Explanation:

4 0
4 years ago
Two reactions and their equilibrium constants are given. A + 2 B − ⇀ ↽ − 2 C K 1 = 2.79 2 C − ⇀ ↽ − D K 2 = 0.186 Calculate the
vfiekz [6]

Answer:

K=1.93

Explanation:

Given reactions are:

A +2B ⇄ 2C  K1=2.79

2C ⇄ D K2=0.186

D⇄ A+ 2B K=?

If we reverse the reaction then the euillibrium constant also become reciprocal of original value:

3rd reaction is a combination of reciprocal of 1st and 2nd reaction

2C⇄A +2B   1/K1;........................1

D ⇄ 2C  1/K2; ..............................2

On adding 1 and 2

D ⇄A +2B    K=\frac{1}{K1} \times\frac{1}{K2};

K=\frac{1}{2.79} \times\frac{1}{0.186};

K=1.93

4 0
3 years ago
Determine the molar solubility of agi in pure water. ksp (agi) = 8.51 × 10-17.
Alex787 [66]
When the salt AgI dissolves in water it dissociates as follows;
AgI ---> Ag⁺ + I⁻
molar solubility is the number of moles that are dissolved in 1 L of solution.
If molar solubility of AgI is x, then molar solubility of Ag⁺ is x and I⁻ is x.
the formula for solubility product constant - ksp of AgI is given below 
ksp = [Ag⁺][I⁻]
ksp = (x)(x)
ksp = 8.51 x 10⁻¹⁷ 
therefore,
x² = 8.51 x 10⁻¹⁷
x = 9.22 x 10⁻⁹
since molar solubility of AgI is x, then molar solubility of AgI is 9.22 x 10⁻⁹ M
3 0
3 years ago
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