Answer:
In 1 mol of Pb₃(PO₄)₄ occupies 1001.48 grams
Explanation:
This compound is the lead (IV) phosphate.
Grams that occupy 1 mole, means the molar mass of the compound
Pb = 207.2 .3 = 621.6 g/m
P = 30.97 .4 = 123.88 g/m
O = (16 . 4) . 4 = 256 g/m
621.6 g/m + 123.88 g/m + 256 g/m = 1001.48 g/m
Answer:
n₂ =1.4 mol
Explanation:
Given data:
Mass of nitrogen = 2 g
Initial Volume occupy by nitrogen = 1.25 L
Final volume occupy by nitrogen = 25.0 L
Final number of moles = ?
Solution;
Formula:
V₁ / n₁ = V₂ / n₂
Number of moles of nitrogen:
Number of moles = mass/ molar mass
Number of moles = 2 g/ 28 g/mol
Number of moles = 0.07 mol
Now we will put the values in formula:
V₁ / n₁ = V₂ / n₂
n₂ = V₂× n₁ /V₁
n₂ = 25 L × 0.07 mol / 1.25 L
n₂ = 1.75 L. mol / 1.25 L
n₂ =1.4 mol
Answer:
Basic solution
Explanation:
A solution containing 0.005 M potassium hydroxide has a pH of;
pOH= -log[0.005]
pOH= 2.3
But pH+pOH=14
Therefore;
pH= 14-pOH
Hence;
pH= 14-2.3= 11.7
A solution having a pH of 11.3 is clearly a basic solution because this pH indicates a substance that is basic in nature. Hence the answer given.
The empirical formula is Ca₃P₂O₈.
<em>Assume</em> that you have 100 g of the compound.
Then you have 38.76 g Ca, 19.97 g P, and 41.28 g O.
Now, we must convert these <em>masses to moles</em> and <em>find their ratio</em>s.
If the number in the ratio are not close to integers, you <em>multiply them by a numbe</em>r that makes them close to integers.
From here on, I like to summarize the calculations in a table.
<u>Element</u> <u>Mass/g</u> <u> Moles </u> <u> </u><u>Ratio </u> <u> ×2 </u> <u>Integers</u>
Ca 38.76 0.967 07 1.4998 2.9995 3
P 19.97 0.644 82 1 2 2
O 41.28 2.580 0 4.0011 8.0023 8
The empirical formula is Ca₃P₂O₈.
