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KatRina [158]
2 years ago
9

A positive charge traveling north enters a region where the electric field is uniform and points east. This charge will Group of

answer choices continues with the same speed in the same direction slows down speed up veers east veers west
Physics
1 answer:
Bingel [31]2 years ago
6 0

Option D is correct : This positive charge will veer east

It is given that the particle has a positive charge.

So, the <u>direction of the force</u> on the positive charge (and also the acceleration) is in the <u>same direction</u> as the electric field.

Now the<u> electric field is uniform</u> and points in east, the<u> force</u> on it F=qEwill also be pointed towards the east.

The positive charge was initially <u>moving north</u>, which means that the velocity vector was in the direction of north and when a <u>positive charge</u> first reaches an area with an electric field and force pointing east, its velocity vector will change to be along the electric field, or east.

That’s why a<u> positive charge </u>traveling north enters a region where the electric field is uniform and points east will veer east.

Learn more about electric field here brainly.com/question/14372859

#SPJ4

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Answer:16.234^{\circ}C

Explanation:

Given

Mass of object (m)=6 kg

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mass of water(m_w)=600 gm

temperature of water =15

specific heat of water =4.186 j/g-^{\circ}C

Let T be the Final Temperature of water

Here Object Potential Energy is converted into Heat energy which will be absorbed by water

Potential Energy(P.E.)=mgh=6\times 9.81\times 10=588.6 J

Heat supplied=m_wc(\Delta T)

H.E.=600\times 4.186\times (T-16)

588.6=2511.6\times (T-16)

T-16=0.234

T=16.234^{\circ}C

This is not an efficient way of heating water as there is only0.234^{\circ}Cincrease in temperature.

5 0
3 years ago
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Tpy6a [65]

Answer:

Option A

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The speed of a mechanical wave is fastest in the solid medium and the slowest in the gaseous medium. Hence, as the wave traverses from gaseous medium to the solid medium, its speed increases.

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Correct answer choice is:

D. A frequency higher than the original frequency.

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