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Mekhanik [1.2K]
3 years ago
13

If a vector a - b = 2c, a + b = 4c and c = 3i + 4j,find a and b

Physics
1 answer:
iren [92.7K]3 years ago
6 0
Ans:
a = 9i + 12j
b = 3i + 4j

Explanation:
We have two equations:

<span>a - b = 2c --- (A)
</span><span>a + b = 4c --- (B)

and two unknowns:
a = ?
b = ?

Whereas,
c = 3i + 4j

Add equations (A) and (B):
=> a - b = 2c
     a + b = 4c
----------------------
    2a = 6c

=> a = 3c --- (C)
Put the value of vector c in equation (C):

(C) => a = 3(3i + 4j)
=> a = 9i + 12j

Now that we have vector a, put that vector and vector c in equation (A):
(A)=> (9i + 12j) - b = 2(3i + 4j)

=> b = (9i + 12) - (6i + 8j)
=> b = 3i + 4j

Ans:
a = </span>9i + 12j
b = 3i + 4j<span>

</span>
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Two charged objects separated by some distance attract each other. If the charges on both objects are doubled with no change in
beks73 [17]

Answer:

a. the force between them quadruples

Explanation:

The electrostatic force between two charges is given by

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1 and q2 are the two charges

r is the separation between the two charges

In this problem, the charges on both objects are doubled, so

q_1' = 2q_1\\q_2' = 2q_2

While the distance does not change, so the new force will be

F'= k \frac{(2q_1)(2q_2)}{r^2}=4 (k\frac{q_1 q_2}{r^2})=4 F

so, the force will quadruple.

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3 years ago
WORD BANK:
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2 years ago
The overhang beam is subjected to the uniform distributed load having an intensity of w = 50 kn/m. determine the maximum shear s
alex41 [277]
Given:

Uniform distributed load with an intensity of W = 50 kN / m on an overhang beam.

We need to determine the maximum shear stress developed in the beam:

τ = F/A

Assuming the area of the beam is 100 m^2 with a length of 10 m.

τ = F/A
τ = W/l
τ = 50kN/m / 10 m
τ = 5kN/m^2
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8 0
3 years ago
You’ve made the hypothesis that the stepper the slope , the faster a ball will be rolling when it reaches the bottom .
BigorU [14]

Answer:

B) how steep the slope is

Explanation:

Because you have to know how is the influence of the steep of the slope in the time that a ball reaches the bottom. The steep of the slope is the variable that you would have to change in an experiment.

I hope this is useful for you

regards

4 0
3 years ago
A 40 kg skier starts at the top of a 12-meter high slope at the bottom she is traveling 10 m/s how much energy does she lose fri
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Potential energy at top:
PE = mgh
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P.E = 4,708.8 J

Kinetic energy at bottom:
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K.E = 2,000 J

P.E = K.E + Frictional losses
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The answer is D.
7 0
3 years ago
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