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Mekhanik [1.2K]
2 years ago
13

If a vector a - b = 2c, a + b = 4c and c = 3i + 4j,find a and b

Physics
1 answer:
iren [92.7K]2 years ago
6 0
Ans:
a = 9i + 12j
b = 3i + 4j

Explanation:
We have two equations:

<span>a - b = 2c --- (A)
</span><span>a + b = 4c --- (B)

and two unknowns:
a = ?
b = ?

Whereas,
c = 3i + 4j

Add equations (A) and (B):
=> a - b = 2c
     a + b = 4c
----------------------
    2a = 6c

=> a = 3c --- (C)
Put the value of vector c in equation (C):

(C) => a = 3(3i + 4j)
=> a = 9i + 12j

Now that we have vector a, put that vector and vector c in equation (A):
(A)=> (9i + 12j) - b = 2(3i + 4j)

=> b = (9i + 12) - (6i + 8j)
=> b = 3i + 4j

Ans:
a = </span>9i + 12j
b = 3i + 4j<span>

</span>
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On a frictionless horizontal air table, puck A (with mass 0.254 kg ) is moving toward puck B (with mass 0.367 kg ), which is ini
irinina [24]

Answer:

v_a=0.8176 m/s

\Delta K=0.07969 J - 0.0849 J = -0.00521 J

Explanation:

According to the law of conservation of linear momentum, the total momentum of both pucks won't be changed regardless of their interaction if no external forces are acting on the system.

Being m_a and m_b the masses of pucks a and b respectively, the initial momentum of the system is

M_1=m_av_a+m_bv_b

Since b is initially at rest

M_1=m_av_a

After the collision and being v'_a and v'_b the respective velocities, the total momentum is

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K_2=\frac{1}{2}m_av_a'^2+\frac{1}{2}m_bv_b'^2

K_2=\frac{1}{2}0.254Kg (-0.123m/s)^2+\frac{1}{2}0.367Kg (0.651m/s)^2=0.07969 J

The change of kinetic energy is

\Delta K=0.07969 J - 0.0849 J = -0.00521 J

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3 years ago
Which phrase best describes sir isaac newton's contributions to modern science and therefore to the industrial revolution?
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Can you please give the phrases? 

But, I'll help what I can.

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He was also the first scientist to be knighted, which is a great honor, as you can expect. 

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