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VladimirAG [237]

1 year ago

15

A train travels 8.81 m/s in a -51.0° direction. The train accelerated for 2.23 s, changing its velocity to 9.66 m/s in a 37.0° d

irection. What is (delta)x?

1 answer:

Evgen [1.6K]1 year ago

7 0

The value of the $\rm \triangle x$ will be 29.14 m. Delta represent the change.

<h3>What is velocity?</h3>

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The velocity in the part 1;

V₁ = 8.81

The velocity in the part 2;

V₂ = 9.66 m/sec

The resultant of the two vectors of velocity gives the velocity for the connecting path.

$\rm V = \sqrt{8.81 ^2 + 9.66^2 } \\\\ V= 13.07 \ m/sec$

The time period for the train accelerates;

$\rm \triangle x = v \times t \\\\ \triangle x = 13.07 \ m/sec \times 2.23 \ sec \\\\ \triangle x = 29.14 \ m$

Hence the value of the $\rm \triangle x$ will be 29.14 m.

To learn more about the velocity, refer to the link: brainly.com/question/862972.

#SPJ1

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A truck covers 40.0 m in 7.50 s while uniformly slowing down to a final velocity of 2.55 m/s. (a) Find the truck's original spee

iris [78.8K]

Answer:

(a) 8.117 (b) 0.742 $m/sec^2$

Explanation:

We have given distance s =40 m time t=7.5 sec

Final velocity v =2.55 m/sec

From the first equation of motion $v=u-at$ (negative sign because there is retrdation as the truck speed is slowing down )

So $2.55=u-7.5a$ --------------eqn 1

From the second equation of motion $s=ut-\frac{1}{2}at^2$ ( negative sign because there is retrdation as the truck speed is slowing down )

So $40=7.5u-0.5\times a\times 7.5^2$

$40=7.5u-28.125a$ ------------------eqn 2

On solving eqn1 and eqn 2

u=8.117 m/sec and a=-0.742 $m/sec^2$

7 0

3 years ago

You connect a 100-resistor, a 800-mH inductor, and a 10.0-uF capacitor in series across a 60.0-Hz, 120-V (peak) source. The impe

steposvetlana [31]

Answer:

Impedance, Z = 107 ohms

Explanation:

It is given that,

Resistance, R = 100 ohms

Inductance, $L=800\ mH=800\times 10^{-3}\ H=0.8\ H$

Capacitance, $C=10\ \mu F=10\times 10^{-6}\ F=10^{-5}\ F$

Frequency, f = 60 Hz

Voltage, V = 120 V

The impedance of the circuit is given by :

$Z=\sqrt{R^2+(X_C-X_L)^2}$ ...........(1)

Where

$X_C$ is the capacitive reactance, $X_C=\dfrac{1}{2\pi fC}$

$X_C=\dfrac{1}{2\pi \times 60\times 10^{-5}}=265.65\ \Omega$

$X_L$ is the inductive reactance, $X_L={2\pi fL}$

$X_L={2\pi \times 60\times 0.8}=301.59\ \Omega$

So, equation (1) becomes :

$Z=\sqrt{(100)^2+(265.65-301.59)^2}$

Z = 106.26 ohms

or

Z = 107 ohms

So, the impedance of the circuit is 107 ohms. Hence, this is the required solution.

8 0

3 years ago

A car is moving at a velocity of 25 km/h and increases velocity to 1200 km/h in 2 min. what is the acceleration?

OlgaM077 [116]

Answer:

a = 2.72 [m/s2]

Explanation:

To solve this problem we must use the following kinematics equation:

$v_{f} =v_{o} + a*t$

where:

Vf = final velocity = 1200 [km/h]

Vo = initial velocity = 25 [km/h]

t = time = 2 [min] = 2/60 = 0.0333 [h]

1200 = 25 + (a*0.0333)

a = 35250.35 [km/h2]

if we convert these units to units of meters per second squared

$35250.35[\frac{km}{h^{2} }]*(\frac{1}{3600^{2} })*[\frac{h^{2} }{s^{2} } ]*(\frac{1000}{1} )*[\frac{m}{km} ] = 2.72 [\frac{m}{s^{2} } ]$

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2 years ago

A block of mass m=9.0 kg and speed V and is behind a block of mass M= 27 kg and speed of .50 m/s. The surface is frictionless, a

sammy [17]

Answer:

2.06 m/s

Explanation:

From the law of conservation of linear momentum, the sum of momentum before and after collision are equal. Considering this case where we have frictionless surface, no momentum is lost in the process.

Momentum before collision

Momentum is given by p=mv where m and v represent mass. The initial sum of momentum will be 9v+(27*0.5)=9v+13.5

Momentum after collision

The momentum after collision will be given by (9+27)*0.9=32.4

Relating the two then 9v+13.5=32.4

9v=18.5

V=2.055555555555555555555555555555555555555 m/s

Rounded off, v is approximately 2.06 m/s

5 0

3 years ago

An object has a mass of 30 grams and measures 3cmx2cmx1cm. What is the density of the object?

dimulka [17.4K]

The density of the object is the ratio of its mass and volume. From the given dimensions above, we determine the volume through the equation,

V = L x W x H

Substituting,

V = (3 cm)(2 cm)(1 cm) = 6 cm³

From the idea presented above,
d = m/V

Substituting the known values,

d = (30 g)/ (6 cm³) = 5 g/cm³

ANSWER: 5 g/cm³

4 0

3 years ago