Question

A train travels 8.81 m/s in a -51.0° direction. The train accelerated for 2.23 s, changing its velocity to 9.66 m/s in a 37.0° direction. What is (delta)x? ​

Answer 1

The value of the $\rm \triangle x$ will be 29.14 m. Delta represent the change.

What is velocity?

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The velocity in the part 1;

V₁ = 8.81

The velocity in the part 2;

V₂ = 9.66 m/sec

The resultant of the two vectors of velocity gives the velocity for the connecting path.

$\rm V = \sqrt{8.81 ^2 + 9.66^2 } \\\\ V= 13.07 \ m/sec$

The  time period for the train accelerates;

$\rm \triangle x = v \times t \\\\ \triangle x = 13.07 \ m/sec \times 2.23 \ sec \\\\ \triangle x = 29.14 \ m$

Hence the value of the $\rm \triangle x$ will be 29.14 m.

To learn more about the velocity, refer to the link: brainly.com/question/862972.

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