A train travels 8.81 m/s in a -51.0° direction. The train accelerated for 2.23 s, changing its velocity to 9.66 m/s in a 37.0° d
irection. What is (delta)x? 
1 answer:
The value of the will be 29.14 m. Delta represent the change.
The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
The velocity in the part 1;
V₁ = 8.81
The velocity in the part 2;
V₂ = 9.66 m/sec
The resultant of the two vectors of velocity gives the velocity for the connecting path.
The time period for the train accelerates;
Hence the value of the will be 29.14 m.
To learn more about the velocity, refer to the link: brainly.com/question/862972.
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Answer:
λ = 396.7 nm
Explanation:
For this exercise we use the diffraction ratio of a grating
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in general the networks works in the first order m = 1
we can use trigonometry, remembering that in diffraction experiments the angles are small
tan θ = y / L
tan θ = = sin θ
sin θ = y / L
we substitute
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with the initial data we look for the distance between the lines
d =
d = 1 656 10⁻⁹ 1.00 / 0.600
d = 1.09 10⁻⁶ m
for the unknown lamp we look for the wavelength
λ = d y / L m
λ = 1.09 10⁻⁶ 0.364 / 1.00 1
λ = 3.9676 10⁻⁷ m
λ = 3.967 10⁻⁷ m
we reduce nm
λ = 396.7 nm