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NISA [10]
2 years ago
15

It takes the Earth 24 hours to make a complete rotation around its axis. 33% Part (a) What is the period of rotation of the Eart

h in seconds? Grade Summary Deductions0 Potential 100 sin cotan) coso asin) atano acotan) sinh0 tan) acoso Attempts remaining per antemp4) detailed vie cosh0 tanhO cotanhO ODegrees O Radians Hint I give up Hints:-% deduction per hint. Hints remaining:- Feedback: dohction per fcedback ▲ 33% Part (b) What is the angular velocity of the Earth in rad/s? 33% Part (c) Given that Earth has a radius of 6.4 x 106 m at its equator, what is the linear velocity at Earth's surface?
Physics
1 answer:
Paladinen [302]2 years ago
7 0

Answer:

Explanation:

a )

one rotation per 24 hours

Time period of rotation of the earth T =  time / no of rotation

T = 24 x 60 x 60 s / 1

= 86400 s .

b )

angular velocity = angle of rotation in radian / time

in one rotation , angle made at the centre = 2π radian

= 2 x 3.14 radian

angular velocity ω = 2π / T

= 2 x 3.14 / 86400  radian / s

= 72.68 x 10⁻⁶ radian / s

c )

Relation between linear and angular velocity is as follows

v = ω  x R where R is radius of the earth and v is linear velocity .

linear velocity = 72.68 x 10⁻⁶ x 6.4 x 10⁶ m /s

= 465.152 m /s

=

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The full range of frequencies of electromagnetic radiation is called
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<h2>Answer: electromagnetic spectrum </h2>

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3 years ago
Terry can ride 30 miles in 2 hours. If his riding speed is
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Answer:

Explanation:

Terry can ride at a speed of

V = 30 miles in 2hours

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5 0
3 years ago
Read 2 more answers
An object of 4 cm length is placed at a distance of 18 cm in front of a convex mirror of radius of curvature 30 cm. Find the pos
erica [24]

Answer:

The position is 8.18cm from the mirror.

Nature is b=virtual

Size is 1.82cm

Explanation:

Note that for a convex mirror, the image distance and the focal length are negative;

Given

Object height H0 = 4cm

object distance u = 18cm

Radius of curvature R = 30cm

Since f = R/2

f = 30/2

f = -15cm

Recall that:

\frac{1}{f} =\frac{1}{u}+ \frac{1}{v}\\\frac{1}{-15}=\frac{1}{18}+\frac{1}{v}    \\\frac{1}{v} =\frac{1}{-15} -\frac{1}{18}\\ \frac{1}{v} = \frac{-18-15}{270}\\\frac{1}{v} = \frac{-33}{270}\\v=\frac{-270}{33}\\v=-8.18cm

Since the image distance is negative, this shows that the image is a virtual image.

To get the size:

\frac{H_1}{H_0}=\frac{v}{u}\\\frac{H_1}{4}=\frac{8.18}{18}\\18H_i=32.72\\H_i=\frac{32.72}{18}\\H_i= 1.82cm

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3 years ago
Given a force of 88N and an acceleration of 4m/s2 what is the mass
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