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NISA [10]
3 years ago
15

It takes the Earth 24 hours to make a complete rotation around its axis. 33% Part (a) What is the period of rotation of the Eart

h in seconds? Grade Summary Deductions0 Potential 100 sin cotan) coso asin) atano acotan) sinh0 tan) acoso Attempts remaining per antemp4) detailed vie cosh0 tanhO cotanhO ODegrees O Radians Hint I give up Hints:-% deduction per hint. Hints remaining:- Feedback: dohction per fcedback ▲ 33% Part (b) What is the angular velocity of the Earth in rad/s? 33% Part (c) Given that Earth has a radius of 6.4 x 106 m at its equator, what is the linear velocity at Earth's surface?
Physics
1 answer:
Paladinen [302]3 years ago
7 0

Answer:

Explanation:

a )

one rotation per 24 hours

Time period of rotation of the earth T =  time / no of rotation

T = 24 x 60 x 60 s / 1

= 86400 s .

b )

angular velocity = angle of rotation in radian / time

in one rotation , angle made at the centre = 2π radian

= 2 x 3.14 radian

angular velocity ω = 2π / T

= 2 x 3.14 / 86400  radian / s

= 72.68 x 10⁻⁶ radian / s

c )

Relation between linear and angular velocity is as follows

v = ω  x R where R is radius of the earth and v is linear velocity .

linear velocity = 72.68 x 10⁻⁶ x 6.4 x 10⁶ m /s

= 465.152 m /s

=

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Answer:

95 minutes

Explanation:

The Hubble Space Telescope makes one orbit around Earth every 95 minutes. The electromagnetic spectrum shows that visible light is between infrared radiation and ultraviolet radiation. NASA.gov

7 0
3 years ago
The product of charge through, and potential across, an electrical device is:
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5 0
3 years ago
Read 2 more answers
A block rests on a frictionless table on Earth. After a 40-N horizontal force is applied to the block, it accelerates at 9.2 m/s
Paul [167]

Answer:

4.6 \frac{m}{s^2}

Explanation:

Since the table is frictionless, there is no force of dynamic  friction between table an block when the horizontal force is applied to it on Earth. Exactly the same is true when the table is taken to the Moon. Therefore, the Net Force acting on the object in both cases when the object accelerates, is the external horizontal force.

Notice that on Earth and on the Moon, the weight of the object (vertical and pointing up) is compensated by the normal force of the table on the object (pointing up and of the same magnitude as the weight) that precludes movement in the vertical direction. So in both cases, its acceleration will only be due to the horizontal force.

We use the equation for Net Force to find the mass of the object:

F=m*a\\40 N =m * 9.2 \frac{m}{s^2}\\\frac{40}{9.2} kg=m\\m=\frac{40}{9.2} kg

We use this mass (since the mass of the object is a constant independent of where the object is) to find the acceleration the object will experience when the 20 N horizontal force is applied on it on the Moon:

f=m*a\\20N=\frac{40}{9.2} kg*a\\20*9.2=40*a\\\frac{20*9.2}{40} =a\\a=\frac{9.2}{2} \frac{m}{s^2} \\ a=4.6 \frac{m}{s^2}

3 0
4 years ago
The public is not yet able to purchase cars powered by hydrogen fuel cells because engineers have to determine how
Nookie1986 [14]
Probably in real world conditions
3 0
3 years ago
The tensile strength (the maximum tensile stress it can support without breaking) for a certain steel wire is 3000 MN/m2. What i
Orlov [11]

Answer:

The correct answer is "21195 N".

Explanation:

The given values are:

Tensile strength,

= 3000 MN/m²

Diameter,

= 3.0 mm

i.e.,

= 3×10⁻³ m

Now,

The maximum load will be:

=  Tensile \ strength\times Area

On substituting the values, we get

=  (3000\times 10^6)(\frac{\pi}{4} (3\times 10^{-3})^2)

=  (3000\times 10^6)(\frac{3.14}{4} (3\times 10^{-3})^2)

=  21195 \ N

4 0
3 years ago
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