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NISA [10]
3 years ago
15

It takes the Earth 24 hours to make a complete rotation around its axis. 33% Part (a) What is the period of rotation of the Eart

h in seconds? Grade Summary Deductions0 Potential 100 sin cotan) coso asin) atano acotan) sinh0 tan) acoso Attempts remaining per antemp4) detailed vie cosh0 tanhO cotanhO ODegrees O Radians Hint I give up Hints:-% deduction per hint. Hints remaining:- Feedback: dohction per fcedback ▲ 33% Part (b) What is the angular velocity of the Earth in rad/s? 33% Part (c) Given that Earth has a radius of 6.4 x 106 m at its equator, what is the linear velocity at Earth's surface?
Physics
1 answer:
Paladinen [302]3 years ago
7 0

Answer:

Explanation:

a )

one rotation per 24 hours

Time period of rotation of the earth T =  time / no of rotation

T = 24 x 60 x 60 s / 1

= 86400 s .

b )

angular velocity = angle of rotation in radian / time

in one rotation , angle made at the centre = 2π radian

= 2 x 3.14 radian

angular velocity ω = 2π / T

= 2 x 3.14 / 86400  radian / s

= 72.68 x 10⁻⁶ radian / s

c )

Relation between linear and angular velocity is as follows

v = ω  x R where R is radius of the earth and v is linear velocity .

linear velocity = 72.68 x 10⁻⁶ x 6.4 x 10⁶ m /s

= 465.152 m /s

=

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3 years ago
If a bowling ball has a mass of 3 kg, what is its weight?
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6 0
4 years ago
Three objects have velocities that vary with time
Solnce55 [7]

#21

  • initial velocity=u=5m/s
  • Time=t=2s
  • Acceleration=a=1.3m/s²

According to first equation of kinematics

  • v=u+at
  • v=5+1.3(2)
  • v=5+2.6
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#22

#a

  • v1=2+3(3)=2+9=11m/s
  • v2=-8-4(3)=-20m/s
  • v3=1-5(3)=-14m/s

The order is

  • v2<V3<v1

#b

for speed find absolute velocity

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  • S2=|-20|=20m/s
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So order is

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7 0
2 years ago
Read 2 more answers
A toy cork gun contains a spring whose spring constant is 10.0N/m. The spring is compressed 5.00cm and then used to propel a 6.0
valentina_108 [34]

Answer:

The muzzle velocity of this cork is 2 m/s.                                

Explanation:

It is given that,

Spring constant of the spring, k = 10 N/m

Mass of the cork, m = 6 g = 0.006 kg

Initial position of the spring, x = 5 cm = 0.05 m

Final position of the spring, x' = 1 cm = 0.01 m

According to the law of conservation of energy, the initial potential energy of the spring is equal to the sum of final spring potential energy and the kinetic energy of cork such that,

\dfrac{1}{2}kx^2=\dfrac{1}{2}kx'^2+\dfrac{1}{2}mv^2

v is the muzzle velocity of this cork.

kx^2=kx'^2+mv^2      

v=\sqrt{\dfrac{k(x^2-x'^2)}{m}}

v=\sqrt{\dfrac{10\times ((0.05)^2-(0.01)^2)}{0.006}}

v = 2 m/s

So, the muzzle velocity of this cork is 2 m/s. Hence, this is the required solution.

4 0
4 years ago
Read 2 more answers
The area of the pond is approximately equal to the area of a circle with radius 297m. Find the mass of the ice. Answer in kilogr
True [87]

Answer:

<em>mass of the ice is 254980463.8T kg</em>

<em>where T is the value of the thickness omitted in the question.</em>

Explanation:

The ice on Walden Pond is .......... thick. The area of the pond is approximately equal to the area of a circle with radius 297 m. Find the mass of the ice.  Answer in kg.

<em>The value of the thickness of the ice T is omitted, but I will show the solution, and the real answer can be gotten by multiplying the final calculated answer here by the thickness of the ice omitted.</em>

Given the radius of the equivalent circle of the ice = 297 m'

the area of the ice can be gotten from area A = \pi r^{2} = 3.142*297^{2} = 277152.678 m^2

recall that the density of ice p ≅ 920 kg/m^3

also,

density of ice p = (mass of ice, m) ÷ (volume of ice, v)

i.e p = m/v

and,

m = pv

substituting the value of the density of water p into the equation, we have,

mass of the ice, m = 920v ....... equ 1

The volume of the ice above will be = (area of the ice, A) x (thickness of the ice, T)

i.e v = AT

substituting the value of area A into the equation, we have

v =  277152.678T  ......equ 2

substitute value of v into equ 1

mass of the ice, m = 920 x (277152.678T)

mass of the ice, m = 254980463.8T kg

where T is the thickness of the ice

NB: To get the mass, multiply this answer with the thickness T given in the question.

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