All categories

2 years ago

Which number is different for isotopes of the same element?

Chemistry

2 answers:

-BARSIC- [3]2 years ago

8 0

it is option c

no of nucleons

tankabanditka [31]2 years ago

4 0

Answer:

D number of protons or atomic mass

You might be interested in

Is NaCH an element ? why or why not?

Mandarinka [93]

I believe you mean NaCI*, (sodium chloride) . Sodium Chloride is not an element, it is known as an ionic compound, reason being because it forms an ionic bond with Na and CI.

5 0

3 years ago

Read 2 more answers

t physiological pH, the carboxylic acid group of an amino acid will be ________, while the amino group will be ________, yieldin

astraxan [27]

Answer:

At physiological pH,the carboxylic acid group of an amino acid will be deprotonated while the amino group will be protonated,yielding the zwitter ion form.

Explanation:

Deprotonated means removal of protons in an acid base reaction and protonated means addition of protons in an acid base reaction.

Both protonated and de protonated reaction takes place in catalytic acid bade reaction by changing either it's mass or it's charge.

During formation of zwitter ion, the carboxylic acid will be deprotonated by donating the H+ ion while the amino acid is protonated by taking the H+ ion.

R-CH-COOH R-CH-COO-

I ⇒ I

NH₂ NH₃ (Zwitter ion)

5 0

3 years ago

The electrophilic bromination or chlorination of benzene requires ______ along with the halogen.

Oksanka [162]

The electrophilic bromination or chlorination of benzene requires Lewis acid along with the halogen.

<h3>What is bromination of benzene?</h3>

The bromination or chlorination of benzene is an example of an electrophilic aromatic substitution reaction.

During the reaction, the bromine forms a sigma bond to the benzene ring, yielding an intermediate. Subsequently a a proton is removed from the intermediate to form a substituted benzene ring.

This reaction is achieved with the help of Lewis acid as catalysts.

Thus, the electrophilic bromination or chlorination of benzene requires Lewis acid along with the halogen.

Learn more about bromination of benzene here: brainly.com/question/26428023

8 0

2 years ago

If the cardboard square has a light on it what do observe

DaniilM [7]

Answer:you observe the light?

Explanation:

3 0

3 years ago

Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calcu

Monica [59]

Answer: The volume of the 1.224 M NaOH solution needed is 26.16 mL

Explanation:

In order to prepare the dilute NaOH solution, solvent is added to a given amount of the NaOH stock solution up to a final volume of 250.0 mL.

Since only solvent is added, the amount of the solute, NaOH, in the dilute solution is the same as in the volume taken from the stock solution.

Molarity (M) is calculated from the following equation:

M = n ÷ V

where n is the number of moles of the solute in the solution, and V is the volume of the solution.

Accordingly, the number of moles of the solute is given by

n = M x V

Now, let's designate the stock NaOH solution and the dilute solution as (1) and (2), respectively . The number of moles of NaOH in each of these solutions is:

n (1) = M (1) x V (1)

n (2) = M (2) x V (2)

As the amount of NaOH in the dilute solution is the same as in the volume taken from the stock solution,

n (1) = n (2)

and

M (1) x V (1) = M (2) x V (2)

For the stock solution, M (1) = 1.244 M, and V (1) is the volume needed. For the dilute solution, M (2) = 0,1281 M, and V (2) = 250.0 mL.

The volume of the stock solution needed, V (1), is calculated as follows:

V (1) = M (2) x V (2) ÷ M (1)

V (1) = 0.1281 M x 250.0 mL ÷ 1.224 M

V (1) = 26.16 mL

The volume of the 1.224 M NaOH solution needed is 26.16 mL.

7 0

3 years ago