All categories

2 years ago

Which number is different for isotopes of the same element?

Chemistry

2 answers:

-BARSIC- [3]2 years ago

8 0

it is option c

no of nucleons

tankabanditka [31]2 years ago

4 0

Answer:

D number of protons or atomic mass

You might be interested in

“Highest molecular motion, highest kinetic energy, no forces of attraction, least dense packaging of molecules.” which state of

Anna [14]

I think its c because solid,liquid nor plasma really fits to the description and i don't really know the last one so the best option is probably C.

7 0

3 years ago

Read 2 more answers

How many grams of hydrogen gas would be needed to form 8.0 grams of water? H2+O2=H2O

damaskus [11]

8 H2= 0.90 g , hope that helps
you with your work

7 0

3 years ago

What is the correct definition of a mixture?

jeka57 [31]

Answer:

a substance made by mixing other substances together.

Explanation:

A mixture is a substance made by mixing two or more substances together.

4 0

3 years ago

Read 2 more answers

Examine the reactants of the incomplete double-displacement reaction. 2NaCl + H2SO4 → __________. Which of the answer choices co

saw5 [17]

C because the sodium (cation) bonds with the sulphate (anion) and then chloride (anion) and hydrogen (acting as a cation) bond together

8 0

3 years ago

Three kilograms of steam is contained in a horizontal, frictionless piston and the cylinder is heated at a constant pressure of

lakkis [162]

Answer:

Final temperature: 659.8ºC

Expansion work: 3*75=225 kJ

Internal energy change: 275 kJ

Explanation:

First, considering both initial and final states, write the energy balance:

$U_{2}-U_{1}=Q-W$

Q is the only variable known. To determine the work, it is possible to consider the reversible process; the work done on a expansion reversible process may be calculated as:

$dw=Pdv$

The pressure is constant, so: $w=P(v_{2}-v_{1} )=0.5*100*1.5=75\frac{kJ}{kg}$ (There is a multiplication by 100 due to the conversion of bar to kPa)

So, the internal energy change may be calculated from the energy balance (don't forget to multiply by the mass):

$U_{2}-U_{1}=500-(3*75)=275kJ$

On the other hand, due to the low pressure the ideal gas law may be appropriate. The ideal gas law is written for both states:

$P_{1}V_{1}=nRT_{1}$

$P_{2}V_{2}=nRT_{2}\\V_{2}=2.5V_{1}\\P_{2}=P_{1}\\2.5P_{1}V_{1}=nRT_{2}$

Subtracting the first from the second:

$1.5P_{1}V_{1}=nR(T_{2}-T_{1})$

Isolating $T_{2}$ :

$T_{2}=T_{1}+\frac{1.5P_{1}V_{1}}{nR}$

Assuming that it is water steam, n=0.1666 kmol

$V_{1}=\frac{nRT_{1}}{P_{1}}=\frac{8.314*0.1666*373.15}{500} =1.034m^{3}$

$T_{2}=100+\frac{1.5*500*1.034}{0.1666*8.314}=659.76$ ºC

7 0

3 years ago