Red shift in the light coming towards us from other galaxies.
Answer:
1. The image is real
2. 5.85
3. h' = 3.05 mm
4. The image is upright
Explanation:
1. Start with the first lens and apply 1/f = 1/p + 1/q
1/5.01 = 1/13.7 + 1/q
q = 7.90 cm
Since that distance is behind the first lens, and the second lens is 62.5 cm behind the first lens, that distance is 62.5 - 7.90 = 54.6 cm in front of the second lens, and becomes the object for that lens, thus,
1/25.9 = 1/54.6 + 1/q
q = 49.3 cm behind the second lens
Using that information, since q is positive, the image is real
2. Also, using that information, you have the second answer, which is 49.3 cm
The height can be found from the two magnifications.
m = -q/p
m1 = -7.9/13.7 = -.577
m2 = -49.3/54.6 = -.903
Net m = (-.577)(-.903) = .521
Then, m = h'/h
.521 = h'/5.85
3. h' = 3.05 mm
4. For the fourth answer, since the overall magnification is positive, the final image is upright
Answer:
The heavier one will have twice the kinetic energy of the lighter one.
Explanation:
For the objects of mass m and 2 m , kinetic energy is
0.5 m v² and 0.5 (2 m) v² respectively. So kinetic energy of the mass 2 m is Twice that of the object of mass m, since their final velocities are equal.
When an object is dropped from the top of a building ( or from some height), its acceleration is equal to the acceleration due to gravity and has a zero initial velocity. On reaching the ground, the final velocity attained by the object depends only on the gravity and the height of fall, as given by the equation v = √2 g h.
So final velocity is independent of the mass of the object. But kinetic energy is 0.5 m v² , which shows that it depends on the mass of the object and square of the velocity.
Given what we know, we can confirm that amongst the wave types mentioned both X-rays and radio waves are able to transmit energy through a vacuum.
<h3>How can these waves propagate through a vacuum?</h3>
This is due to the fact that unlike sound, water, and seismic waves that transmit energy through air, water, or the earth, the waves mentioned above, those being radio and x-rays, do not need a medium through which to propagate. This allows them to exist and transmit energy even in a vacuum such as outer space, which is corroborated by their existence in space.
Therefore, we can confirm that amongst the wave types mentioned both X-rays and radio waves are able to transmit energy through a vacuum.
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Wavelength = (speed) / (frequency)
= (30 m/s) / (60/sec) =
= 0.5 meter .