Stephen`s Law:
P = (Sigma) · A · e · T^4
P in = P out
e = 1 for blacktop;
1150 W = (Sigma) · T^4
(Sigma) = 5.669 · 10 ^(-8) W/m²K^4
T^4 = 1150 : ( 5.669 · 10^(-8) )
T^4 = 202.875 · 10^8
![T = \sqrt[4]{202.857 * 10 ^{8} }](https://tex.z-dn.net/?f=T%20%3D%20%20%5Csqrt%5B4%5D%7B202.857%20%2A%2010%20%5E%7B8%7D%20%7D%20)
T = 3.774 · 10² =
377.4 KAnswer: Equilibrium temperature is 377.4 K.
Answer:
b) Vectors A and B are in the same direction.
Explanation:
To understand this problem we will say that vector A has a magnitude of 5 units and vector B a magnitude of 3 units. In the subtraction of vectors the initial parts of vectors always bind together. And the vector resulting from the subtraction is traced from the end of the second vector (B) to the end of the first vector (A).
The length of the resultant vector will be 5 - 3 = 2
In the attached image, we analyze case a), b), and d)
For a)
As we can see in the attached image the resultant vector has a length of 8 units.
For d)
As we can see in the attached image the resultant vector has a length of 5.83 units.
For b)
The resultant vector has a length of 2 units.
Therefore the case given in b) is true
Answer:
i know the questin but i got to try and find it
Explanation:
<h3>
Answer:</h3>
1.5 m/s²
<h3>
Explanation:</h3>
We are given;
Force as 60 N
Mass of the Cart as 40 kg
We are required to calculate the acceleration of the cart.
- From the newton's second law of motion, the rate of change in momentum is directly proportional to the resultant force.
- That is, F = ma , where m is the mass and a is the acceleration
Rearranging the formula we can calculate acceleration, a
a = F ÷ m
= 60 N ÷ 40 kg
= 1.5 m/s²
Therefore, the acceleration of the cart is 1.5 m/s²
