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TiliK225 [7]
3 years ago
12

Consider four atoms from the second period: lithium, beryllium, boron, carbon, and nitrogen. Which of these emblems has the lowe

st electronegativity value?
•Lithium
•Beryllium
•Boron
•Carbon
•Nitrogen
Physics
1 answer:
xz_007 [3.2K]3 years ago
6 0
If you go to the right along the periodic table, electronegativity increases.
So the larger the column number, the greater the electronegativity.

-Lithium has lowest as it is in the 1st column



-Beryllium (2nd column)
-Boron s (13th column)
-Nitrogen (15th column)


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2 years ago
An ideal battery would produce an extraordinarily large current if "shorted" by connecting the positive and negative terminals w
liubo4ka [24]

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Explanation:

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Need help with physics please
bazaltina [42]

The centripetal force : F = 293.3125 N

<h3>Further explanation</h3>

Given

mass = 65 kg

v = 9.5 m/s

r = 20 m

Required

the centripetal force

Solution

Centripetal force is a force acting on objects that move in a circle in the direction toward the center of the circle  

\large {\boxed {\bold {F = \frac {mv ^ 2} {R}}}

F = centripetal force, N  

m = mass, Kg  

v = linear velocity, m / s  

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Input the value :

F = 65 x 9.5² / 20

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