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2 years ago

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Physics

1 answer:

Elena-2011 [213]2 years ago

7 0

The cost of the 1.4KW kettle is 0.945 p.

<h3>What is the cost of electricity?</h3>

The cost of electricity is computed from the cost of electricity. We have to know the cost of electricity that is charged for the 1.4kW kettle.

Now let the power consumed=

1.4kW * 0.075 hrs = 0.105 KWhr

Then;

1 KWhr costs 9p

0.105 KWhr costs 0.105 KWhr * 9p/1 KWhr

= 0.945 p

Learn more about cost of electricity:brainly.com/question/16948772

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A positive point charge (q = +5.45 x 10-8 C) is surrounded by an equipotential surface A, which has a radius of rA = 1.49 m. A p

ruslelena [56]

Answer:

$r_{B} = 3.34\ m$

Solution:

As per the question:

Point charge, q = $5.45\times 10^{- 8}\ C$

Test charge, $q_{o} = 4.96\times 10^{- 11}\ C$

Work done by the electric force, $W_{AB} = - 9.05\times 10^{- 9}\ J$

Now,

We know that the electric potential at a point is given by:

$V = \frac{kqq'}{r}$

where

r = separation distance between the charges.

Also,

The work done by the electric force i moving a test charge from point A to B in an electric field:

$W_{AB} = kqq_{o}(\frac{1}{r_{B} - \frac{1}{r_{A}}}$

$- 9.05\times 10^{- 9} = 9\times 10^{9}\times 5.45\times 10^{- 8}\times 4.96\times 10^{- 11}(\frac{1}{r_{B}} - \frac{1}{1.49}}$

$- 0.3719 = (\frac{1}{r_{B}} - 0.67}$

$r_{B} = \frac{1}{0.299} = 3.34\ m$

5 0

3 years ago

A relatively small impact crater 20 kilometers in diameter could be made by a comet 2 kilometers in diameter traveling at 25 km/

nadya68 [22]

Answer:

$KE=1.3\times 10^{21}\ J$

$KE=3.1\times 10^{5}\ E$

Explanation:

(a)

Given:

mass of comet, $m=4.2\times 10^{12}\ kg$

velocity of the comet, $v=2.5\times 10^4\ m.s^{-1}$

<u>Now, the kinetic energy of the comet can be given by:</u>

$KE=\frac{1}{2} m.v^2$

$KE=0.5\times 4.2\times 10^{12}\times (2.5\times 10^4)^2$

$KE=1.3\times 10^{21}\ J$

(b)

Given:

energy released by 1 megaton of TNT, $E=4.2\times 10^{15}\ J$

<u>Now the kinetic energy of the comet in terms of energy of 1 megaton TNT:</u>

$KE=\frac{1.3\times 10^{21}}{4.2\times 10^{15}} E$

i.e.

$KE=3.1\times 10^{5}\ E$

4 0

3 years ago

2. A rock is dropped off a bridge. How fast is the rock

zhenek [66]

Answer:

a) The velocity of rock at 1 second, v = 9.8 m/s

b) The velocity of rock at 3 second, v = 29.4 m/s

c) The velocity of rock at 5.5 second, v = 53.9 m/s

Explanation:

Given data,

The rock is dropped from a bridge.

The initial velocity of the rock, u = 0

a) The velocity of rock at 1 second,

Using the first equation of motion

v = u + gt

v = 0 + 9.8 x 1

v = 9.8 m/s

b) The velocity of rock at 3 second,

v = u + gt

v = 0 + 9.8 x 3

v = 29.4 m/s

c) The velocity of rock at 5.5 second,

v = u + gt

v = 0 + 9.8 x 5.5

v = 53.9 m/s

5 0

3 years ago

A student wants to determine the impulse delivered to the lab cart when it runs into the wall. The student measures the mass of

forsale [732]

Impulse = Force * times and also Impulse = change in momentum.

Given that the mass does not change, change if momentum = mass * (final velocity - initial velocity)

Given that you know mass and initial velocity (which is the velicity before the cart hits the wall) you need the final velocity (which is the velocity after the cart hits the wall).

Answer: the velocity of the cart after it hits the wall.

6 0

3 years ago

If are spaced closely together on the map,there is a drastic temperature change over the distance

AlexFokin [52]

If <em>the isotherms</em> are spaced closely together over some portion of the map, there is a drastic temperature change over that portion.

6 0

3 years ago

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