Ask question

Ask question

All categories

3 years ago

15

You venture out on a cold winter morning to warm up your vehicle. You have layers of cotton/polyester blend clothes on and from

walking on carpeting you have accumulated a net negative charge. Your car is considered a neutral conductor. As you place your hand near the door handle (without touching it) what happens to the charges of your car?

1 answer:

xxMikexx [17]3 years ago

4 0

Answer:

There is a localization of negative charge near the door handle.

You might be interested in

A car that travels from point A to point B in four hours, and then from point B back to point A in six hours. The road between p

Hitman42 [59]

Note : Be careful with speed and velocity, even the formula is same that $v = \frac{x}{t}$

1. If we would like to find the velocity, we must calculate the distance from initial to final, $x_{f} - x_{i} = (delta)x$ ,

2. If we would like to find the speed, we must calculate the total distance that travelled ( $x_{total}$ .

So, in this question, because it return back to its initial point so (delta)x = 0, so average velocity is 0 m/s.

3 0

3 years ago

Read 2 more answers

What is the λ (in m) of an electromagnetic wave that has a frequency of 5.68 x 107 Hz? Enter a numerical response in 3 significa

denpristay [2]

Answer:

Wavelength of electromagnetic wave will be 5.281 m

Explanation:

We have given frequency of electromagnetic wave is $f=5.68\times 10^7Hz$

Velocity of electromagnetic wave is $c=3\times 10^8m/sec$

We have to fond the wavelength of the electromagnetic wave

We know that velocity of electromagnetic eave is given by $v=\lambda f$ , here $\lambda$ is wavelength and f is frequency

So $\lambda =\frac{v}{f}=\frac{3\times 10^8}{5.68\times 10^7}=5.281m$

Wavelength of electromagnetic wave will be 5.281 m

6 0

3 years ago

A wheel is rotating at 30.0 rpm. The wheel then accelerates uniformly to 50.0 rpm in 10.0 seconds. Determine the – a) rate of an

Mademuasel [1]

Answer:

The angular acceleration is $0.209\ rad/s^2$

Explanation:

Given that,

Angular velocity, $\omega_{i} = 30.0\ rpm$

Angular velocity, $\omega_{f} = 50.0\ rpm$

Time t = 10.0 sec

We need to calculate the angular acceleration

Using formula of angular acceleration

$\alpha=\dfrac{\Delta \omega}{\Delta t}$

$\alpha=\dfrac{\omega_{f}-\omega_{i}}{\Delta t}$

$\alpha=\dfrac{50.0-30.0}{10.0}$

Now, we change the angular velocity in rad/s.

$\omega=20\times\dfrac{2\pi}{60}$

$\omega=2.09\ rad/s$

$\alpha=\dfrac{2.09}{10.0}$

$\alpha=0.209\ rad/s^2$

Hence, The angular acceleration is $0.209\ rad/s^2$

5 0

3 years ago

Read 2 more answers

Two velcro-covered pucks slide across the ice, collide and stick to one another. Their interaction with the ice is frictionless.

balu736 [363]

Answer:

<em>1. False</em>

<em>2. True</em>

<em>3. False</em>

<em>4. True</em>

Explanation:

<u>Conservation of Momentum</u>

According to the law of conservation of linear momentum, the total momentum of the system formed by both pucks won't change regardless of their interaction if no external forces are acting on the system.

The momentum of an object of mass ma moving at speed va is

$p_a=m_a.v_a$

The total momentum of both pucks at the initial condition is

$p_1=m_a.v_a+m_b.v_b$

Both pucks are moving to the right and puck B has twice the mass of puck A (let's call it m), thus

$m_a=m$

$m_b=2m$

We are given

$v_a=6\ m/s\\v_b=2\ m/s$

The total initial momentum is

$p_1=6m+2(2m)=10m$

At the final condition, both pucks stick together, thus the total mass is 3m and the final speed is common, thus

$p_2=3m.v'$

Equating the initial and final momentum

$10m=3m.v'$

Solving for v'

$v'=10/3\ m/s=3.33\ m/s$

1. Compute the initial kinetic energy:

$\displaystyle K_1=\frac{1}{2}mv_a^2+\frac{1}{2}2mv_b^2$

$\displaystyle K_1=\frac{1}{2}m\cdot 6^2+\frac{1}{2}2m\cdot 2^2$

$K_1=18m+4m=22m$

The final kinetic energy is

$\displaystyle K_2=\frac{1}{2}mv'^2+\frac{1}{2}2mv'^2$

$\displaystyle K_2=\frac{1}{2}m\cdot 3.33^2+\frac{1}{2}2m\cdot 3.33^2$

$K_2=16.63m$

As seen, part of the kinetic energy is lost in the collision, thus the statement is False

2. The initial speed of puck B was 2 m/s and the final speed was 3.33 m/s, thus it increased the speed: True

3. The initial speed of puck A was 6 m/s and the final speed was 3.33 m/s, thus it decreased the speed: False

4. The momentum is conserved since that was the initial assumption to make all the calculations. True

$p_1=10m$

$p_2=3m.v'=3m(10/3)=10m$

Proven

5 0

3 years ago

9.5 g bullet has a speed of 1.5 km/s what is the kinetic energy of the bullet

Amiraneli [1.4K]

The answer is 0.000824653J

You need to use the formula Mass * Velocity^2 over 2

3 0

3 years ago

Read 2 more answers