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lisabon 2012 [21]
2 years ago
13

What are the characteristics of a " team " in hit in volleyball ? ​

Physics
1 answer:
Lostsunrise [7]2 years ago
5 0

Answer:

<em>A team may contact the ball a total of </em><em>three (3) times</em><em> before it is sent over the net. </em>

<em />

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A shopper pushes a 5.32 kg grocery cart
Juli2301 [7.4K]

Answer:

\text { acceleration of the cart is } 10.94 \mathrm{m} / \mathrm{s}^{2}

Explanation:

According to “Newton's second law”

“Force” is “mass” times “acceleration”, or F = m× a. This means an object with a larger mass needs a stronger force to be moved along at the same acceleration as an object with a small mass

Force = mass × acceleration

\text { Acceleration }=\frac{\text { force }}{\text { mass }}

Given that,

Mass = 5.32 kg

\text { Force }=12.7 \mathrm{N} \text { forces at }-28.7^{\circ}

x=-28.7^{\circ}

F = 12.7N

Normal force = mg + F sinx,  

“m” being the object's "mass",  

“g” being the "acceleration of gravity",

“x” being the "angle of the cart"

\mathrm{g}=9.8 \mathrm{m} / \mathrm{s}^{2}\text { (g is referred to as the acceleration of gravity. Its value is } 9.8 \mathrm{m} / \mathrm{s}^ 2 \text { on Earth })

To find normal force substitute the values in the formula,

Normal force = 5.32 × 9.8 + 12.7 × sin(-28.7)

Normal force = 52.136 + 12.7 × 0.480

Normal force = 52.136 + 6.096

Normal force = 58.232 N

<u>Acceleration of the cart</u>:

\text { Acceleration }=\frac{\text {Normal force}}{\text { mass }}

\text { Acceleration }=\frac{58.232}{5.32}

\text { Acceleration }=10.94 \mathrm{m} / \mathrm{s}^{2}

\text { Therefore, "acceleration of the cart" is } 10.94 \mathrm{m} / \mathrm{s}^{2}

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2 years ago
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A 6.72 particle moves through a region of space where an electric field of magnitude 1270 N/C points in the positive direction,
Romashka [77]

Answer:

                    v_{y}  = -104 m/s

Explanation:

Using:

Force = electric field * charge

F=e*q

Force = magnitude of charge * velocity * magnetic field * sin tither

F_{x2}= |q|*v*B*sin \alpha

Force on particle due to electric field:

     F_{x1}= E*q = (1270N/C)*(-6.72*10^{-6} ) = -8.53*10^{-3}

Force on particle due to magnetic field:

F_{x2}= |q|*v*B*sin \alpha  = (6.72*10^{-6} )*(1.15)*(sin90)*v = (7.728*10^{-6})*(v)

F_{x2} is in the positive x direction as F_{x1} is in the negative x direction while net force is in the positive x direction.

Magnetic field is in the positive Z direction, net force is in the positive x direction.

According to right hand rule, Force acting on particle is perpendicular to the direction of magnetic field and velocity of particle. This would mean the force is along the y-axis. As this is a negatively charged particle, the direction of the velocity of the particle is reversed. Therefore velocity of particle, v, has to be in the negative y direction.

Now,

                    F_{xnet}- F_{x1 } = F_{x2 }

                    (6.13*10^{-3}) - (8.53*10^{-3} ) = (7.728*10^{-6})*(v)

                    v = (F_{xnet}  - F_{x1}) / (F_{x2} )

                        =((6.13*10^{-3} ) - (8.53*10^{-3})) / (7.728*10^{-6})

                       = (- 104.25) m/s

                      v_{y}  = -104 m/s

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Third parties may also help voter turnout by bringing more people to the polls. Third party candidates at the top of the ticket can help to draw attention to other party candidates down the ballot, helping them to win local or state office.

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