<span>59.027m/s^2
Centripetal force is give by F = mv^2/r
Since
F = ma
The acceleation accoiated with this centripetal force is
a=v^2/r
the radius is found by r=d/2=5.75m
velocity is found by
v=d/t
distance is the circumference of the circle
c=pi*d=11.5*3.14=36.11m
time=60s/30.6rpm=1.96s
v=36.11/1.96=18.423m/s
plugging this back in to
a=v^2/r=(18.423m/s)^2/5.75m=59.027m/s^2</span>
Answer:
5.98 km
Explanation:
This question can be easily solved by using the trigonometric properties of a right angled triangle.
See attachment for pictorial explanation
To get x we have
Sinθ = opp / hyp
Sin25 = x / 4.5
x = 4.5 sin 25
x = 4.5 * 0.423
x = 1.9 km
To get y, we have
Cosθ = adj / hyp
Cos25 = y / 4.5
y = 4.5 cos 25
y = 4.5 * 0.906
y = 4.08 km
x + y = 1.9 + 4.09 = 5.98 km
Thus, the minimum distance required is 5.98 km
Answer:
(a) E = [2ξ] / [1+2]]
(b) S = k.ln(1+2) + [ξ] / T[1+2]]
(c) S = k.ln 3 (These values directly obtained from the result of (b) when T⇒0 & T⇒∞.)
Explanation:
Given:
One of three quantum states labeled by the quantum numbers m,
Where m = -1 , 0 or 1
A nucleus has the same energy E= e in the state m = 1 & m = -1
Compared with an energy E = 0 in the state m = 0.
Answer:
v = 17.9 m/s
Explanation:
As we know that the normal force measured by the sensor before the ride is started is given as
now when the rider has reached at the top position of the loop then the normal force is given as
now at the top position we have
so we have