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Oduvanchick [21]
2 years ago
10

If the same total travel at the speed of 0.05 m/s for 40 seconds, how far would it have gone?

Physics
1 answer:
Ymorist [56]2 years ago
4 0

Answer:

Would've traveled 2 miles.

Explanation:

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C. Transform boundary
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When Stone B collides with Stone A during Test 2, Stone B stops and Stone A begins to move. Which statement BEST describes the m
Anna11 [10]

Answer:

A

Explanation:

According to law of conservation of momentum, the total momentual in the system will be conserved

5 0
2 years ago
A newly discovered planet has a mean radius of 7380 km. A vehicle on the planet\'s surface is moving in the same direction as th
Butoxors [25]

Answer:

292796435 seconds ≈ 300 million seconds

Explanation:

First of all, the speed of the car is 121km/h = 33.6111 m/s

The radius of the planet is given to be 7380 km = 7380000 m

From the relationship between linear velocity and angular velocity i.e., v=rw, the angular velocity of the car will be w=v/r = 33.6111/7380000 = 0.000000455 rad/s = 4.55 x 10⁻⁶ rad/sec

If the angular velocity of the vehicle about the planet's center is 9.78 times as large as the angular velocity of the planet then we have

w(vehicle) = 9.78 x w(planet)

w(planet) = w(vehicle)/9.78 = 4.55 x 10⁻⁶ / 9.78 = 4.66 x 10⁻⁷ rad/sec

To find the period of the planet's rotation; we use the equation

w(planet) = 2π÷T

Where w(planet) is the angular velocity of the planet and T is the period

From the equation T = 2π÷w = 2×(22/7) ÷  4.66 x 10⁻⁷ = 292796435 seconds

Therefore the period of the planet's motion is 292796435 seconds which is approximately 300, 000, 000 (300 million) seconds

8 0
3 years ago
How can air particles be trapped for investigation? (Subject: Science)
zhannawk [14.2K]
-- Find a clean jar that has a tight lid.
-- Take the lid off of the jar.
-- Wave the jar around for a while.
-- Put the lid back on the jar, tightly.

You now have a jar full of air and everything in the air.
You can take it into your laboratory and have your way with it.
3 0
2 years ago
Two tougboats are toeing a ship each exerts a force of 6000N and the angle between the two ropes is 60 calculate the resultant f
Arlecino [84]

Answer:

10392.30N

Explanation:

We proceed by computing the individual force exerted by the boats

For the first boat

The angle is 30 degree to the vertical

Hence

Force = F cos θ

F=6000 cos 30

F=6000*0.866

F=5196.15 N

Since the boats are two and also at the same angle and also exerting the same force

The Net force = 2*5196.15

Net force=10392.30N

7 0
2 years ago
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