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kobusy [5.1K]
3 years ago
7

Tim, with mass 53.5 kg, climbs a gymnasium

Physics
1 answer:
Stella [2.4K]3 years ago
7 0
Potential energy = mgh

= 53.5 x 9.8 x 4.7

= 2464.21 Joules
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Determine weather or not the equation below is balanced.
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Answer:

Yep.. It's balanced and its a combination reaction

Explanation:

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Product 8SF₆

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A person who is described as intersex is
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I believe it means they are born with both parts that a man and woman would be born with.
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Studen
Vesna [10]

Complete Question

A football coach walks 18 meters westward, then 12 meters eastward, then 28 meters westward, and finally 14 meters eastward.

a

From this motion what is the distance covered

b

What is the magnitude and direction of the displacement

Answer:

a

  D =   72 \  m

b

Magnitude

             d =  - 20 \ m

 Direction  

West

Explanation:

From the question we are told that

The first distance covered westward is d_w_1  =  18 \  m /tex]     The  first distance covered eastward is [tex]d_e1 =  12 \  m /tex]      The second distance covered westward is [tex]d_w_2  =  28 \  m /tex]      The  second distance covered eastward is [tex]d_e2 =  14 \  m /tex]   Generally the distance covered is mathematically represented as       [tex]D =  d_w1 + d_w2 + d_e1 + d_e2

=> D =   18 + 28 + 12 +  14

=> D =   72 \  m

For the second question eastward is in the direction of the positive x-axis so it would be positive and westward is in the direction of the negative x-axis so it would be negative

The magnitude of the displacement is

d =  -d_w1 -d_w2 + d_e1 + d_e2

=>  d =  -18-28 + 12 + 14

=> d =  - 20 \ m

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d.

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You are tossing a ball directly up into the air. Before the ball leaves your hand, you are exerting a force directed against the
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Answer:

F n = 0.2 N

Explanation:

given,                                      

you are exerting force of 10 N on the ball.

mass of the ball = 1 kg              

acceleration due to gravity  = 9.8 m/s²

normal force on the ball = ?          

normal force is force exerted by the object to counteract the force from other object.                

normal force acting on the ball will be

F n = F - mg                          

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F n = 0.2 N            

Hence, normal force acting on the ball is equal to 0.2 N

7 0
3 years ago
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