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2 years ago

Navigation is the art of measuring distances in order to be able to __________.

Physics

1 answer:

Kaylis [27]2 years ago

7 0

Navigation is the art of measuring distances in order to be able to get from one place to another

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Freeeee pointsssssss. i hope yall have a good as well!! Also, whats something you regret doing most?

leonid [27]

Answer:POGGERS thx i rl needed this have a good day also something a regret the most is searching up henhai i am now addicted

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3 years ago

Read 2 more answers

A large helium filled balloon is used as the center piece for a graduation party. The balloon alone has a mass of 225 kg and it

Orlov [11]

To solve this problem it is necessary to apply the concepts related to Newton's second law, the definition of density and sum of forces in bodies.

From Newton's second law we understand that

$F= ma (\rightarrow$ Gravity at this case)

Where,

m = mass

a= acceleration

Also we know that

$\rho = \frac{m}{V} \Rightarrow m = \rho V$

Part A) The buoyant force acting on the balloon is given as

$F_b = ma$

As mass is equal to the density and Volume and acceleration equal to Gravity constant

$F_b = \rho V g$

$F_b = 1.2*323*9.8$

$F_b = 3798.5$

PART B) The forces acting on the balloon would be given by the upper thrust force given by the fluid and its weight, then

$F_{net} = F_b -W$

$F_{net} = F_b -(mg+\rho_H Vg)$

$F_{net} = 3798.5-(9.8*225*9.8*0.179*323)$

$F_{net} = 1030N$

PART C) The additional mass that can the balloon support in equilibrium is given as

$F_{net} = m' g$

$m' =\frac{F_{net}}{g}$

$m' = \frac{1030}{9.8}$

$m' = 105Kg$

4 0

4 years ago

The food calorie, equal to 4186 J, is a measure of how much energy is released when food is metabolized by the body. A certain b

d1i1m1o1n [39]

It’s definitely gonna be A

5 0

3 years ago

Calculate the work done by an 85.0-kg man who pushes a crate 4.00 m up along a ramp that makes an angle of 20.0° with the horizo

Aleks [24]

Answer: Given mass of man = 85kg

Distance crate was pushed = 4m

Force exerted on crate = 500N

Angle inclined = 20°

Let Total force exerted Ft = (mg * sin(20)) + 500

Ft =( 85*9.81* sin20°) + 500

Ft = 758N

Work done Wd = Ft * distance

Wd = 785 * 4 = 3.14 * 10^3J

3 0

3 years ago

A proton and an electron are released from rest in the center of a capacitor.

Sunny_sXe [5.5K]

Answer:

a) equal 1, b) less than 1

Explanation:

a) the electric force is given by

Fe = q E

The charge of the electron and proton has the same value, that of the proton is positive and that of the electron is negative

Proton

Fp = qE

Electron

Fe = - q E

Fp / Fe = -1

If we do not take into account the sign the relationship is equal to one (1)

b) to calculate the force we use Newton's second law

F = ma

qE = m a

a = q E / m

The mass of the proton much greater than the mass of the electron

ap = q E / $m_{p}$

ae = - q E / $m_{e}$

ap / ae = $m_{e}$ / $m_{p}$ = $m_{e}$ /1600 $m_{e}$ =1/1600

It is much smaller than 1

7 0

3 years ago