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2 years ago

Can you put this image back together? Type the correct order of letters below.

Physics

1 answer:

Art [367]2 years ago

6 0

Answer:

CABD

.....................

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How did you do it i still can't figure it out

Elena-2011 [213]

Answer:

can you ask clear questions I did not understand your question

7 0

3 years ago

A rocket accelerates at 25m/s^2 for 5s before it runs out of fuel and dies. What is the maximum height reached by the rocket?

sineoko [7]

Answer:

1109m

Explanation:

The distance h₁ traveled by the rocket during acceleration:

$h_1=\frac{1}{2}at^2$

The velocity v₁ at this height h₁:

$v_1=at$

When the rocket runs out of fuel, energy is conserved:

$E=\frac{1}{2}mv_1^2+mgh_1=mgh_2$

Solving for h₂:

$h_2=\frac{v_1^2}{2g}+h_1=\frac{(at)^2}{2g}+\frac{1}{2}at^2$

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3 years ago

Please help it’s urgent!

mariarad [96]

(,I hope this helps yoy)

Explanation:

1.If the displacement of an object is zero,the speed must be zero.

Not true

2.(your answer is true)

3.false

4.true

4 0

3 years ago

A positive point charge (q = +8.65 x 10-8 C) is surrounded by an equipotential surface A, which has a radius of rA = 2.97 m. A p

ella [17]

Answer:

$r_B = 1.88 m$

Explanation:

As we know that work done by electric force is given as

$W_e = -q\Delta V$

so here we know that charge is moving from

$r_A = 2.97 m$

to another position

so we will have

$W_{AB} = \frac{kq_1q_2}{r_A} - \frac{kq_1q_2}{r_B}$

$-6.95\times 10^{-9} = (9\times 10^9)(8.65\times 10^{-8})(4.56\times 10^{-11})(\frac{1}{2.97} - \frac{1}{r_B})$

$-0.196 = (\frac{1}{2.97} - \frac{1}{r_B})$

$r_B = 1.88 m$

7 0

4 years ago

Question 4 A car of mass 820 kg has a maximum power of 30 kW and moves against a constant resistance of motion to 910 N. Calcula

wolverine [178]

Answer:

P = W / t = m g s / t = m g v where work by auto = m g s

30 kw = 30000 watts = 30000 J / s

Work wasted = F v as shown above relating work and power

Work done against incline = m g s sin 8.75 and power against incline

= m g v sin 8.75 = 1222 v Joules / sec

power in moving auto = power available - power lost to friction

power in moving auto = 30000 - resistance = 30000 - 910 v

1222 v = 30000 - 910 v

v = 30000 / 2132 = 14 m/s

Note: constant resistance to motion must mean P = W / t = F s / t = F v

7 0

3 years ago