The distance of the Image will be -33.75 cm
A concave mirror has an inward-curving reflecting surface that faces away from the light source. Unlike convex mirrors, a concave mirror's image forms a variety of images based on the object's proximity to the mirror.
Given that, an object placed 27 cm from a concave mirror having the focal length of 15 cm
We have to find distance of the Image
Using Mirror Formula:
1/f = 1/v + 1/u
Where,
f = focal length
v = Image distance from the mirror
u = object distance from the mirror (concave)
Substitute the known values in the above formula to find the value of 'v' i.e. from the mirror.
1/(-15) = 1/v + 1/(-27)
1/(-15) = 1/v - (1/27)
1/v = -0.029
v = -33.75 cm
Therefore the distance of the Image will be -33.75 cm
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Answer:
- The solubility of the salt is 35.16 (g/100 g of water).
- It would take 71.09 grams of water to dissolve 25 grams of salt.
- The percentage of salt that dissolves is 52.7 %
Explanation:
<h3>
a.</h3>
We know that 3.20 grams of salt in 9.10 grams of water gives us a saturated solution at 25°C. To find how many grams of salt will gives us a saturated solution in 100 grams of water at the same temperature, we can use the rule of three.
Working it a little this gives us :
So, the solubility of the salt is 35.16 (g/100 g of water).
<h3>
b.</h3>
Using the rule of three, we got:
Working it a little this gives us :
So, it would take 71.09 grams of water to dissolve 25 grams of salt.
<h3>C.</h3>
Using the rule of three, we got that for 15.0 grams of water the salt dissolved will be:
Working it a little this gives us :
This is the salt dissolved
The percentage of salt dissolved is:
Answer:
Explanation:
This is a simple gravitational force problem using the equation:
where F is the gravitational force, G is the universal gravitational constant, the m's are the masses of the2 objects, and r is the distance between the centers of the masses. I am going to state G to 3 sig fig's so that is the number of sig fig's we will have in our answer. If we are solving for the gravitational force, we can fill in everything else where it goes. Keep in mind that I am NOT rounding until the very end, even when I show some simplification before the final answer.
Filling in:
I'm going to do the math on the top and then on the bottom and divide at the end.
and now when I divide I will express my answer to the correct number of sig dig's:
6.45 × 10¹⁶ N
Answer:
Radio emissions of hydrogen and OH molecules
Explanation:
Water hole is a quiet region of the electromagnetic spectrum
