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Fofino [41]
2 years ago
14

How many moles of PCl5 can be produced from 28.0 g of P4 (and excess Cl2 )? Express your answer to three significant figures and

include the appropriate units.
Chemistry
1 answer:
umka2103 [35]2 years ago
5 0

0.903 mol of PCl₅ can be produced from 28.0 g of P₄ (and excess Cl₂).

<h3>What is Stoichiometry ?</h3>

Stoichiometry helps us to use the balanced chemical equation to measure the quantitative relationship and it is to calculate the amount of product and reactants that are given in a reaction.

<h3 /><h3>What is Balanced Chemical Equation ?</h3>

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now write the balanced chemical equation

P₄ + 10 Cl₂ → 4PCl₅

1 mole of P₄ react with 10 mole of Cl₂ produces 4 moles of PCl₅.

According to Stoichiometry

\frac{n_{P_4}}{1} = \frac{n_{PCl_5}}{4}

n_{P_4} = \frac{\text{Given Mass}}{\text{Molar mass}}

      = \frac{28\ g}{124\ g/mol}

      = 0.22580645161 mol

Now put the value in above equation

\frac{n_{P_4}}{1} = \frac{n_{PCl_5}}{4}

\frac{0.22580645161}{1} = \frac{n_{PCl_5}}{4}

n_{PCl_5} = 0.903 mol

Thus from the above conclusion we can say that 0.903 mol of PCl₅ can be produced from 28.0 g of P₄ (and excess Cl₂).

Learn more about the Stoichiometry here: brainly.com/question/25829169

#SPJ4

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Answer:

= 529.9422

grams

Explanation:

5  moles Sodium Carbonate

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8 0
3 years ago
Find the potential energy of a 2 kg ball 15 m in the air.
amm1812

Answer:

294,3

Explanation:

E=m*g*h

While g = 9,81 m/s^2 then:

E=2[kg]*9,81[\frac{m}{s^2} ]*15[m]=294,3 [J] [J]

7 0
3 years ago
What is the mass of 2N at 0.2829 atm 1.35 L and 25°C
maria [59]
<h3>Answer:</h3>

0.437 g

<h3>Explanation:</h3>

From the question we have;

Pressure of the gas as 0.2829

Volume of the gas as 1.35 L

Temperature of the gas as 25°C

But, K = °C + 273.15

Therefore, temperature of the gas is equivalent to 298.15 K

We are required to calculate the mass of the gas

<h3>Step 1: Number of moles of the gas </h3>

Using the ideal gas equation, PV = nRT , we can determine the number of moles.

R is the ideal gas constant, 0.082057 L.atm/mol.K

Therefore, rearranging the formula;

n = PV ÷ RT

 = (0.2829 atm × 1.35 L) ÷ (0.082057 × 298.15 K)

 = 0.0156 mole

Therefore, the number of moles of the gas is 0.0156 mole

<h3>Step 2: Mass of the gas </h3>

We know that mass of a compound is the product of moles and the molar mass.

Mass = Moles × Molar mass

Molar mass of the gas is 28.0134 g/mol

Therefore;

         = 0.0156 mole × 28.0134 g/mol

         = 0.437 g

Thus, the mass of the gas is 0.437 g

5 0
4 years ago
What quaintly represents .500 mole at STP?
s2008m [1.1K]
.500 moles is roughly
.5 * 6.022 * 10^23 = 3.011*10^23 atoms. this is independent of STP
if it’s wrong i’m sorry
3 0
3 years ago
Read 2 more answers
Which element is not conserved in this unbalanced chemical equation?
Yuri [45]
D. Na

There are 2 Na in the reactants, and only 1 Na in the product.
8 0
3 years ago
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