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Fofino [41]
2 years ago
14

How many moles of PCl5 can be produced from 28.0 g of P4 (and excess Cl2 )? Express your answer to three significant figures and

include the appropriate units.
Chemistry
1 answer:
umka2103 [35]2 years ago
5 0

0.903 mol of PCl₅ can be produced from 28.0 g of P₄ (and excess Cl₂).

<h3>What is Stoichiometry ?</h3>

Stoichiometry helps us to use the balanced chemical equation to measure the quantitative relationship and it is to calculate the amount of product and reactants that are given in a reaction.

<h3 /><h3>What is Balanced Chemical Equation ?</h3>

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now write the balanced chemical equation

P₄ + 10 Cl₂ → 4PCl₅

1 mole of P₄ react with 10 mole of Cl₂ produces 4 moles of PCl₅.

According to Stoichiometry

\frac{n_{P_4}}{1} = \frac{n_{PCl_5}}{4}

n_{P_4} = \frac{\text{Given Mass}}{\text{Molar mass}}

      = \frac{28\ g}{124\ g/mol}

      = 0.22580645161 mol

Now put the value in above equation

\frac{n_{P_4}}{1} = \frac{n_{PCl_5}}{4}

\frac{0.22580645161}{1} = \frac{n_{PCl_5}}{4}

n_{PCl_5} = 0.903 mol

Thus from the above conclusion we can say that 0.903 mol of PCl₅ can be produced from 28.0 g of P₄ (and excess Cl₂).

Learn more about the Stoichiometry here: brainly.com/question/25829169

#SPJ4

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Suppose the half-life is 9.0 s for a first order reaction and the reactant concentration is 0.0741 M 50.7 s after the reaction s
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<u>Explanation:</u>

The equation used to calculate half life for first order kinetics:

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k = rate constant = ?

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k=\frac{0.693}{9}=0.077s^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}     ......(1)

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k = rate constant  = 0.077s^{-1}

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[A_o] = initial amount of the reactant = ?

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Putting values in equation 1, we get:

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Putting values in equation 1, we get:

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