Answer:
there are 6 significant figures in 107.051
Answer:
The temperatures of the objects must be different
Explanation:
if heat is flowing between two objects, then the objects must be at different temperatures.
<h3><u>Full Question:</u></h3>
The following compound has been found effective in treating pain and inflammation (J. Med. Chem. 2007, 4222). Which sequence correctly ranks each carbonyl group in order of increasing reactivity toward nucleophilic addition?
A) 1 < 2 < 3
B) 2 < 3 < 1
C) 3 < 1 < 2
D) 1 < 3 < 2
<h3><u>Answer: </u></h3>
The rate of nucleophilic attack of carbonyl compounds is 2<3 <1.
Option B
<h3><u>Explanation. </u></h3>
Nucleophilic attack is explained as the attack of an electron rich radical to a carbonyl compound like aldehyde or a ketone. A nucleophile has a high electron density, so it searches for a electropositive atom where it can donate a portion of its electron density and become stable.
A carbonyl compound is a
hybridized carbon atom with a double bonded oxygen atom in it. The oxygen atom pulls a huge portion of electron density from carbon being very electropositive.
In a ketone, there are two factors that make it less likely to undergo a nucleophilic attack than aldehyde. Firstly, the steric hindrance of two carbon groups being attached with the carbonyl carbon makes it harder for the nucleophile to approach. Secondly, the electron push by the carbon groups attached makes the carbonyl carbon a bit less electropositive than the aldehyde one. So aldehydes are more reactive towards a nucleophilic addition reaction.
Answer : The percent purity of
in the original sample is 87.94 %
Explanation :
The given balanced chemical reaction is:

First we have to calculate the mass of Fe.

Molar mass of Fe = 55.8 g/mole

Now we have to calculate the moles of 
From the balanced chemical reaction we conclude that,
As, 2 moles of Fe produced from 1 mole of 
So,
of Fe produced from
mole of 
Now we have to calculate the mass of 

Molar mass of
= 159.69 g/mole

Now we have to calculate the percent purity of
in the original sample.
Mass of original sample = 


Therefore, the percent purity of
in the original sample is 87.94 %