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Degger [83]
3 years ago
10

Calculate the gravitational potential energy of the interacting pair of the Earth and a 11 kg block sitting on the surface of th

e Earth. You would need to supply the absolute value of this result to move the block to a location very far from the Earth (actually, you would need to use even more energy than this due to the gravitational potential energy associated with the Sun-block interacting pair).
Physics
1 answer:
trasher [3.6K]3 years ago
5 0

Answer:

Gravitational potential energy (GPE) = 107.8J

Explanation:

Gravitational potential energy (GPE) = mgh

Where mass(m) = 11kg

Acceleration due to gravity(g) = 9.8m²/s

height = assumed to be 1m

Force(F) = mg

Force(F) = 11×9.8 = 107.8N

Gravitational potential energy (GPE) = 107.8×1

= 107.8J

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Explanation:

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4 0
3 years ago
You have a double slit experiment, with the distance between the two slits to be 0.025 cm. A screern is 120 cm behind the double
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Answer:

The wavelength of the light is 633 nm.

Explanation:

Given that,

Distance between the two slits d= 0.025 cm

Distance between the screen and slits D = 120 cm

Distance between the slits y= 1.52 cm

We need to calculate the angle

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\tan\theta=\dfrac{y}{D}

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\tan\theta=\dfrac{1.52}{120}

\theta=\tan^{-1}\dfrac{1.52}{120}

\theta=0.725

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d\sin\theta=n\lambda

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0.025\times\sin0.725=5\times\lambda

\lambda=\dfrac{0.025\times10^{-2}\times\sin0.725}{5}

\lambda=6.326\times10^{-7}\ m

\lambda=633\ nm

Hence, The wavelength of the light is 633 nm.

4 0
3 years ago
The acceleration of gravity is -9.8 m/s2. A sling shot fires a rock straight up into the air with a speed of +39.2 m/s. 1. what
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Given that,

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v = 19.6 m/s

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B is the awser 
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How are period and frequency related to each other?
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Frequency refers to the number of occurrences of a periodic event per time and is measured in cycles/second. In this case, there is 1 cycle per 2 seconds. ... Frequency is the reciprocal of the period. The period is 5 seconds, so the frequency is 1/(5 s) = 0.20 Hz
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