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Degger [83]
3 years ago
10

Calculate the gravitational potential energy of the interacting pair of the Earth and a 11 kg block sitting on the surface of th

e Earth. You would need to supply the absolute value of this result to move the block to a location very far from the Earth (actually, you would need to use even more energy than this due to the gravitational potential energy associated with the Sun-block interacting pair).
Physics
1 answer:
trasher [3.6K]3 years ago
5 0

Answer:

Gravitational potential energy (GPE) = 107.8J

Explanation:

Gravitational potential energy (GPE) = mgh

Where mass(m) = 11kg

Acceleration due to gravity(g) = 9.8m²/s

height = assumed to be 1m

Force(F) = mg

Force(F) = 11×9.8 = 107.8N

Gravitational potential energy (GPE) = 107.8×1

= 107.8J

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Answer:

2. 4.63 x 10 to the -11th power

Explanation:

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m1 · m2 = 3.1 · 6.3 = 19.5

d² = 5.3² = 28.1

19.5/28.1 = 0.694

(6.67 · 10^-11) · 0.694 = 4.63 × 10^-11

7 0
2 years ago
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Irina18 [472]

Answer:

235.8 N

Explanation:

Given that

Jack

83.5 east

Jill

93.3√2/2 east

93.3√2/2 north

Jane

121√2/2 east

121√2/2 south

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Fx = 83.5 + 93.3√2/2 + 121√2/2

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Fy = 93.3√2/2 - 121√2/2

Fy = 65.97 - 85.56

Fy = -19.59 N (south)

Finding the resultant, we have

F = √(Fx²+Fy²)

F = √(235² + (-19.59)²)

F = √55225 + 383.7681

F = √55608.7681

F = 235.8 N

4 0
3 years ago
When storm clouds produce lightning and thunder, energy changes to energy and energy.
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Maybe the word could be converted?
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The best question that could prompt a scientific investigation is: <u>What substances dissolve in ocean water?</u> 

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3 years ago
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