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gizmo_the_mogwai [7]
2 years ago
12

Figure 13 shows a child’s toy . The toy hangs from a hook in the ceiling.

Physics
1 answer:
Grace [21]2 years ago
6 0

The number of oscillations of the toy in a second is 1.25.

<h3>What is frequency?</h3>
  • This is the number of complete oscillation of an object is a given period.

The given parameter:

  • Frequency of the toy, F = 1.25 Hz

The frequency of an object is calculated as follows;

f = \frac{n}{t} \\\\

where;

  • n is the number of oscillations
  • t is the time of motion

The number of oscillations of the toy in a second is calculated as follows;

1.25 = \frac{n}{1} \\\\n = 1.25

Learn more about frequency here: brainly.com/question/10728818

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Answer:

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Solution:

As per the question:

Length of the coil, l = 12 cm = 0.12 m

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Now,

Area of cross-section of the wire, A = \frac{\pi d^{2}}{4} = \frac{\pi \times 0.017^{2}}{4} = 2.269\times 10^{- 4}\ m^{2}

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L = \frac{mu_{o}AN^{2}}{l} = \frac{4\pi \times 10^{- 7}\times 2.269\times 10^{- 4}\times 235^{2}}{0.12} = 1.312\times 10^{- 4}\ H = 13.12\ mH

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