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RUDIKE [14]
2 years ago
10

Why do lunar and solar eclipses not happen every month?

Chemistry
1 answer:
White raven [17]2 years ago
5 0
A lunar eclipse occurs when The moon’s orbit is tilted five degrees from earth’s orbit around the sun .
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The actual yield of a product in a reaction was measured as 4.20 g. If the theoretical yield of the product for the reaction is
Norma-Jean [14]

\frac{actual yield}{theoretical yield}*100

\frac{4.20}{4.88}*100

<u>86.1%</u>

5 0
4 years ago
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Can anyone answer 10.4? (45 points if correct)
otez555 [7]
Alpha is the -OH group at the anomeric position is down. beta is up

a. alpha
b. beta
c. beta
d. alpha

to draw the other anomer, just flip the OH at the anomeric position

3 0
3 years ago
Help me please. Which type of plate boundary is responsible for volcanoes and mountain building?
adoni [48]
Answer: B. divergent

6 0
3 years ago
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Be sure to answer all parts. Consider the reaction A + B → Products From the following data obtained at a certain temperature, d
worty [1.4K]

Answer : The order of reaction with respect to A is, first order reaction.

The order of reaction with respect to B is, zero order reaction.

The overall order of reaction is, first order reaction.  

Explanation :

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

A+B\rightarrow Products

Rate law expression for the reaction:

\text{Rate}=k[A]^a[B]^b

where,

a = order with respect to A

b = order with respect to B

Expression for rate law for first observation:

3.20\times 10^{-1}=k(1.50)^a(1.50)^b ....(1)

Expression for rate law for second observation:

3.20\times 10^{-1}=k(1.50)^a(2.50)^b ....(2)

Expression for rate law for third observation:

6.40\times 10^{-1}=k(3.00)^a(1.50)^b ....(3)

Dividing 1 from 2, we get:

\frac{3.20\times 10^{-1}}{3.20\times 10^{-1}}=\frac{k(1.50)^a(2.50)^b}{k(1.50)^a(1.50)^b}\\\\1=1.66^b\\b=0

Dividing 1 from 3, we get:

\frac{6.40\times 10^{-1}}{3.20\times 10^{-1}}=\frac{k(3.00)^a(1.50)^b}{k(1.50)^a(1.50)^b}\\\\2=2^a\\a=1

Thus, the rate law becomes:

\text{Rate}=k[A]^1[B]^0

\text{Rate}=k[A]

Thus,

The order of reaction with respect to A is, first order reaction.

The order of reaction with respect to B is, zero order reaction.

The overall order of reaction is, first order reaction.

7 0
3 years ago
How many electrons can s,p,d,f hold?
oksian1 [2.3K]

s-orbital = 2 elec.

p-orbital = 6 elec.

d-orbital = 10 elec.

f-orbital = 14 elec.

7 0
4 years ago
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