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Pavel [41]
3 years ago
9

What kind of light would be the best to use to look inside a cold dark cloud and see the warm stars forming inside?

Physics
1 answer:
lys-0071 [83]3 years ago
7 0
<h2>Answer: Infrared light</h2>

A dark nebula is a cloud of dust and cold gas, which does not emit visible light and hides the stars it contains.

These types of nebulae are composed mainly of the hydrogen they obtain from nearby stars, which is their fuel.

It is using infrared light that we can "observe" and analyze in detail what happens in the inner parts of these nebulae.

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A solid cylinder (1 =1/2mr2 ) with a mass of 4.83 kg and a radius of 0.057 m starts
netineya [11]

Answer:

v = 7.32 m/s

Explanation:

The potential energy will convert to kinetic energy

        ½Iω² + ½mv² = mgh

             Iω² +  mv² = 2mgh

(½mR²)(v/R)² + mv² = 2mgh

           ½mv² + mv² = 2mgh

                 ½v² + v² = 2gh

                      3v²/2 = 2gh

                           v² = 4gh/3

                           v² = 4(9.81)(4.10)/3

                           v² = 53.628

                            v = 7.323114...

                            v = 7.32 m/s

3 0
3 years ago
Elect the correct equations that show that when a 3.0-kg book is lifted 2.6 m its increase in gravitational potential energy is
grigory [225]
The increase in gravitational potential energy for an object of mass m is given by
\Delta U = mg \Delta h
where \Delta h is the increase in altitude of the object.

In our problem, m=3.0 kg, \Delta h= 2.6 m and g=10 m/s^2 (approximated value), so we have
\Delta U = mg\Delta h=(3.0 kg)(10 m/s^2)(2.6 m)=78 J
5 0
3 years ago
Electrical current is defined as
lbvjy [14]

The answer is B. It is measured in amperes.

5 0
3 years ago
A 0.850 kg block is attached to a spring with spring constant 18 N/m . While the block is sitting at rest, a student hits it wit
Sveta_85 [38]

The block's speed at the point where x=0.25A is v = 31.95 cm/s.

<h3>What is Spring constant?</h3>

The spring stiffness is quantified by the spring constant, or k. For various springs and materials, it varies. The stiffer the spring is and the harder it is to stretch, the bigger the spring constant.

question is incomplete, this is the remaining statement

What is the amplitude of the subsequent oscillations? And What is the block's speed at the point where x=0.25A?

x = Asin(wt)

v = Aw coswt

at t = 0

w = sqrt(k/m)

v = Aw

A = v/w

A = 7.17 cm

part b )

E = 1/2mv^2 + 1/2kx^2 = 1/2kA^2

mv^2 + k(1/4A)^2 = 1/2kA^2

mv^2 + kA^2/16 = kA^2

mv^2 = kA^2 - kA^2/16

mv^2 = 15kA^2/16

v^2 = 15/16 * (k/m) * A^2

v^2 = 15/16 *w^2A^2

v = sqrt(15/16) * wA

v = 31.95 cm/s

to learn more about spring constant go to -

brainly.com/question/23885190

#SPJ4

8 0
2 years ago
Choose if the quantity indicated is a vector or a scalar. Quantity: the number of coins in a piggy bank Type of quantity:
Kitty [74]
Vector quantities are always defined by magnitude and its direction.
Here, to define number of coins in a piggy bank, we don't need direction. Hence it is a scalar quantity.
7 0
3 years ago
Read 2 more answers
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