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nignag [31]
3 years ago
7

What is the minimum coefficient (ms) of static friction between the road and the car? Since the net force is equivalent to the f

orce of static friction, your answer to Part D (9000 N) is the magnitude of force of static friction (fs). Based on this value, what is the minimum coefficient (ms) of static friction between the road and the car?
Physics
1 answer:
kirill115 [55]3 years ago
3 0
            Best Answer:  <span> fnet = umg </span>
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How much work is done by gravity when a pine cone (of mass 50g) falls from the top of a tree, 9 m high?
Ksenya-84 [330]

4.5 Joules. I think it'd be 4.41, but when you round it, it's 4.5.

5 0
3 years ago
. Inside a conducting sphere of radius 1.2 m, there is a spherical cavity of radius 0.8 m. At the center of the cavity is a poin
MAVERICK [17]

Answer:

 E = 1,873 10³ N / C

Explanation:

For this exercise we can use Gauss's law

        Ф = E. dA = q_{int} / ε₀

Where q_{int} is the charge inside an artificial surface that surrounds the charged body, in this case with the body it has a spherical shape, the Gaussian surface is a wait with radius r = 1.35 m that is greater than the radius of the sphere.

The field lines of the sphere are parallel to the radii of the Gaussian surface so the scald product is reduced to the algebraic product.

        The surface of a sphere is

             A = 4π r²

             E 4π r² = q_{int} /ε₀

  The net charge within the Gauussian surface is the charge in the sphere of q1 = + 530 10⁻⁹ C and the point charge in the center q2 = -200 10⁻⁹ C, since all the charge can be considered in the center the net charge is

           q_{int} = q₁ + q₂

           q_{int} = (530 - 200) 10⁻⁹

           q_{int} = 330 10⁻⁹ C

The electric field is

             E = 1 / 4πε₀   q_{int} / r²

            k = 1 / 4πε₀

            E = k q_{int}/ r²

Let's calculate

           E = 8.99 10⁹   330 10⁻⁹/ 1.32²

           E = 1,873 10³ N / C

7 0
3 years ago
Marcia pokes fun at her husband Brian because he loves to sing in the shower every morning, but
Masteriza [31]

Answer:

<em>Since I can see no choices, I answered it in my own understanding.</em>

Brian - amplitude and frequency

Marcia - amplitude and longitudinal wave

Explanation:

"Sound" and "sound waves" are essential part of a person's life. They can be used for<u> communicating</u> and <u>detecting some object</u>s.

Brian loves singing in the shower which means that he is using a greater amplitude. Amplitude refers to the<em> intensity of the sound </em>or the amount of energy that a sound carries. When one sings in the shower, the sound cannot travel very far. It bounces immediately back to the person singing thus, making the sound bigger. Brian is also using a <em>different range of </em><em>frequency</em><em> compared to his normal way of talking.</em> The frequency of a normal male voice is normally 85 to 180 Hz. A person singing may have a frequency as high as 1,500 Hz.

Marcia talks loudly on the phone. This means that she is also using a greater amplitude because the intensity of her voice is big. Since she is using the telephone, this means that her voice travels in a longitudinal wave through the telephone. This allows her voice to reach to the person on the other end of the line.

7 0
3 years ago
. A grindstone increases in angular speed from 4.00 rad/s to 12.00 rad/s in 4.00 s. Through what angle does it turn during that
ZanzabumX [31]

Answer:

\theta=32rad

Explanation:

In an uniformly accelerated circular motion, the angle traveled by the object is given by:

\theta=\frac{\omega_f+\omega_0}{2}t

Here \omega_f is the final angular speed, \omega_0 is the initial angular speed and t is the time of the motion. Replacing the given values:

\theta=\frac{12\frac{rad}{s}+4\frac{rad}{s}}{2}(4s)\\\theta=32rad

5 0
3 years ago
How much conventional current must you run in a solenoid with radius = 0.05 m and length = 0.39 m to produce a magnetic field in
Ugo [173]

Answer:

Explanation:

radius of the solenoid, r = 0.05 m

length of the solenoid, l = 0.39 m

Magnetic field of the solenoid, B = 2 x 10^-5 T

Number of turns, N = 200

The magnetic field of the solenoid is given by

B=\mu _{0}ni

where, i be the current and n be the number of turns per unit length

n = N / l = 200 / 0.39 = 512.8

2\times 10^{-5}=4 \times 3.14\times 10^{-7}\times 512.8\times i

i = 0.031 A

3 0
3 years ago
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