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andrew-mc [135]
2 years ago
5

You matter .Until you Multiply yerself by the speed of Light Squared. Then you Energy.​

Physics
2 answers:
iragen [17]2 years ago
6 0

Answer:

Hellow ❤️

.

.

Gooood Morning

andriy [413]2 years ago
6 0

Answer:

?

Explanation:

I thought we were talking about a Flashpoint or something?

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Calculate the work done by a force of 30 N in lifting a load of 2 kg to a height of 10 m (g = 10 m/s2)
Mars2501 [29]

Answer:

<u>300 J</u>

Explanation:

Given :

  1. Applied force = 30 N
  2. Mass = 2 kg
  3. Height = 10 m
  4. g = 10 m/s²

Work done by the force :

  • Work done = Force x Displacement
  • Work done = mg x h
  • Work done = 30 N x 10 m
  • Work done = <u>300 J</u>

<u></u>

<u><em>Note</em></u> :

  • What you have calculated is the work done by gravitational force on the object (that too, incorrectly)
  • But in the end, it asks for work done by the force of 30N
  • Hence, the given answer ~
3 0
2 years ago
When an object reflects all the light waves that strike it looks white or black?
egoroff_w [7]
Light waves can be from any color, depends on what it is bouncing no or reflecting off of.
3 0
3 years ago
(50 POINTS) HELP!!!!!! WILL GIVE BRAINLIEST
zepelin [54]
C) During chemical reaction, total mass remains the same.

This is because due to the law of conservation of mass, stating that in a chemical reaction, neither mass will be created nor destroyed. So, the total mass will not change when chemical reactions occur.
7 0
2 years ago
A jet plane is launched from a catapult on an aircraft carrier. In 2.0 s it reaches a speed of 42 m/s at the end of the catapult
Dennis_Churaev [7]

First find Acceleration

  • Initial velocity=u=0m/s
  • Final velocity=v=42m/s
  • Time=t=2s
  • Distance=s
  • Acceleration=a

\boxed{\sf Acceleration=\dfrac{v-u}{t}}

\\ \sf\longmapsto Acceleration=\dfrac{42-0}{2}

\\ \sf\longmapsto Acceleration=\dfrac{42}{2}

\\ \sf\longmapsto Acceleration=21m/s^2

Using second equation of kinematics

\boxed{\sf s=ut+\dfrac{1}{2}at^2}

\\ \sf\longmapsto s=0(2)+\dfrac{1}{2}(21)(2)^2

\\ \sf\longmapsto s=21(2)

\\ \sf\longmapsto s=42m

5 0
2 years ago
How much force is required to accelerate a 50 kg mass at 2 m/s2?
-BARSIC- [3]
=0.5 x40 
<span>= (calculate it) </span>
<span>2. F= -.45 x 41 </span>
<span>= </span>
<span>3. F=20 x 12 </span>
<span>= </span>
<span>4. F=50 x 30 </span>
<span>= </span>

<span>I believe you can go on from here, remember its easy </span>

<span>for the last 2 just rearange the formual </span>
<span>for 9 it will be a=F/m and 10. m=f/a </span>
4 0
3 years ago
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