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spayn [35]
3 years ago
15

An echocardiogram uses 4.4 MHz ultrasound to measure blood flow in the aorta. The blood is moving away from the probe at 1.4 m/s

. What is the frequency shift of the reflected ultrasound?
Physics
1 answer:
Alinara [238K]3 years ago
7 0

Answer:

\Delta f=17959.2\ Hz

Explanation:

Given:

  • original frequency of  the wave, f=4.4\times 10^6\ Hz
  • velocity of the blood stream moving away, v=1.4\ m.s^{-1}

<u>Doppler shift is given as:</u>

\frac{f}{f_o} =\frac{s+v_s}{s-v_o}

where:

s = velocity of ultrasound in blood = 1570\ m.s^{-1}

v_s= velocity of sound  source towards the observer

v_o= velocity of the observer away from the source

\frac{4.4\times 10^6}{f_o} =\frac{1570+0}{1570-1.4}

f_o=4396076.43\ Hz

Therefore the shift in frequency:

\Delta f=f-f_o

\Delta f=3923.56\ Hz

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If an object has a mass of 1417g and it is moved 47 meters in 90 seconds, how much power was used?
astraxan [27]

Mass of the object is given as

m = 1417 g = 1.417 kg

now the speed of object is given as

v = \frac{d}{t}

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v = \frac{47}{90} = 0.52 m/s

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14.A 90 kg quarterback gets tackled by being hit by a 120 kg lineman backwards
quester [9]

The acceleration of the quarterback and the lineman is 5.55m/s² and 4.16m/s² respectively in the same direction.

As, we know, the 120 Kg lineman is moving with a force of 500N.

His net acceleration will be in the same direction as his motion.

It is already known that, If M is the mass of the body and a is the acceleration of the body, then the force F on the body can be calculated by using the formula,

F = Ma.

The weight of the quarterback is 90 Kg. He is being hit by a force of 500N.

So, the acceleration can be calculated using the formula,

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a = 5.55 m/s².

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So, from the formula, his acceleration A will be,

500N = 120Kg x A

A = 4.16 m/s².

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Answer:

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