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spayn [35]
3 years ago
15

An echocardiogram uses 4.4 MHz ultrasound to measure blood flow in the aorta. The blood is moving away from the probe at 1.4 m/s

. What is the frequency shift of the reflected ultrasound?
Physics
1 answer:
Alinara [238K]3 years ago
7 0

Answer:

\Delta f=17959.2\ Hz

Explanation:

Given:

  • original frequency of  the wave, f=4.4\times 10^6\ Hz
  • velocity of the blood stream moving away, v=1.4\ m.s^{-1}

<u>Doppler shift is given as:</u>

\frac{f}{f_o} =\frac{s+v_s}{s-v_o}

where:

s = velocity of ultrasound in blood = 1570\ m.s^{-1}

v_s= velocity of sound  source towards the observer

v_o= velocity of the observer away from the source

\frac{4.4\times 10^6}{f_o} =\frac{1570+0}{1570-1.4}

f_o=4396076.43\ Hz

Therefore the shift in frequency:

\Delta f=f-f_o

\Delta f=3923.56\ Hz

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Answer:

a) - 72.5°c

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Explanation:

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T = -131 + ( 0.003 * altitude in meters )

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b) Determine pressure and density at 19.5 km altitude

Given :

Po (atmospheric pressure at sea level )  = 101kpa

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attached below is the remaining part of the solution

C) determine if the aircraft is subsonic or super sonic

Velocity ( v ) = \sqrt{CRT}  =  \sqrt{1.4*287*200.5 } = 283.8 m/s

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Given that a pipe having a diameter of 1.5 feet and a height of 10 feet, what is the psi at 5 feet ?
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Answer:

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Explanation:

Given that,

Diameter = 1.5 feet

Height = 10 feet

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