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spayn [35]
4 years ago
15

An echocardiogram uses 4.4 MHz ultrasound to measure blood flow in the aorta. The blood is moving away from the probe at 1.4 m/s

. What is the frequency shift of the reflected ultrasound?
Physics
1 answer:
Alinara [238K]4 years ago
7 0

Answer:

\Delta f=17959.2\ Hz

Explanation:

Given:

  • original frequency of  the wave, f=4.4\times 10^6\ Hz
  • velocity of the blood stream moving away, v=1.4\ m.s^{-1}

<u>Doppler shift is given as:</u>

\frac{f}{f_o} =\frac{s+v_s}{s-v_o}

where:

s = velocity of ultrasound in blood = 1570\ m.s^{-1}

v_s= velocity of sound  source towards the observer

v_o= velocity of the observer away from the source

\frac{4.4\times 10^6}{f_o} =\frac{1570+0}{1570-1.4}

f_o=4396076.43\ Hz

Therefore the shift in frequency:

\Delta f=f-f_o

\Delta f=3923.56\ Hz

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You walk with a velocity of 2 m/s north. You see a man approaching you, and from your frame of
solong [7]

Answer:

The velocity of the man from the frame of  reference of a stationary observer is, V₂ = 5 m/s

Explanation:

Given,

Your velocity, V₁ = 2 m/

The velocity of the person, V₂ =?

The velocity of the person relative to you, V₂₁ = 3 m/s

According to the relative velocity of two

                                V₂₁ = V₂ -V₁

∴                               V₂ =  V₂₁ + V₁

On substitution

                                 V₂ = 3 + 2

                                      = 5 m/s

Hence, the velocity of the man from the frame of reference of a stationary observe is, V₂ = 5 m/s

8 0
3 years ago
What is the magnitude of the orbital velocity of the earth in m/s?
Lana71 [14]
Circumference C=2πr 
<span>C=2π(1.5x10^8)=9.42x10^8 </span>

<span>In 365 Days there are 8760hr </span>

<span>V=distance/time </span>

<span>V=(9.42x10^8)/8760=107534.2km/hr </span>
8 0
3 years ago
Astronomers know that the distance between the Earth and the Sun averages 1.50 x108 km. How can astronomers use the observed ste
rodikova [14]

Answer:

The distance of stars and the earth can be averagely measured by using the knowledge of geometry to estimate the stellar parallax angle(p).

From the equation below, the stars distances can be calculated.

D = 1/p

Distance = 1/(parallax angle)

Stellar parallax can be used to determine the distance of stars from an observer, on the surface of the earth due to the motion of the observer. It is the relative or apparent angular displacement of the star, due to the displacement of the observer.

Explanation:

Parallax is the observed apparent change in the position of an object resulting from a change in the position of the observer. Specifically, in the case of astronomy it refers to the apparent displacement of a nearby star as seen from an observer on Earth.

The parallax of an object can be used to approximate the distance to an object using the formula:

D = 1/p

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3 0
3 years ago
If I were to transmit a radio wave in our three dimensional world could a fourth dimensional “being” be able to receive it?
Morgarella [4.7K]
Depends. Are you talking about a mathematical 4th dimension (in which there is infinite dimensions) or some sort of etheral dimension (in which there is no scientific evidence for)

If you mean the first then yes. But it depends how these beings exist. From our understanding we only can theorize shapes in 4-d and if we assume that there is only one universe these "beings" arleady exist and thus any message in 3-d would be sent to them like a shadow ("flat").
If they exist in a alternate "plane" then you would need some method to transverse this plan and if u did, then we would easily be able to communicate, but we would at first sound like a wild animal. They either would ignore us, not understand or perceive us, or they would attempt to send back a signal (essential they are ET's)

IF you mean the second then thats some mystic stuff and its pretty creepy (although a fun read for me :P)
 
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5 0
3 years ago
What distance will a car cover while uniformly accelerating from 12m/s to 26m/in 14 seconds​
VikaD [51]

Answer:

Distance = 266m

Explanation:

6 0
4 years ago
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