Preserved fossil<span> (like a fossil in amber, ice or tar.</span>
Answer:
1.265 Pounds
Explanation:
Data provided:
Tire outside diameter = 49"
Rim diameter = 22"
Tire width = 19"
Now,
1" = 0.0254 m
thus,
Tire outside radius, r₁ = 49"/2 = 24.5" = 24.5 × 0.0254 = 0.6223 m
Rim radius, r₂ = 22" / 2 = 11" = 0.2794 m
Tire width, d = 19" = 0.4826 m
Now,
Volume of the tire = π ( r₁² - r₂² ) × d
on substituting the values, we get
Volume of air in the tire = π ( 0.6223² - 0.2794² ) × 0.4826 = 0.46877 m³
Also,
Density of air = 1.225 kg/m³
thus,
weight of the air in the tire = Density of air × Volume air in the tire
or
weight of the air in the tire = 1.225 × 0.46877 = 0.5742 kg
also,
1 kg = 2.204 pounds
Hence,
0.5742 kg = 0.5742 × 2.204 = 1.265 Pounds
An iron pot is mostly magnetic
Answer: 1.33
Explanation:
We would apply Snell's law which is expressed as
niSinθi = nrSinθr
where
θi = angle of incidence
θr = angle of refraction
ni = index of refraction of the incident medium(air)
nr = index of refraction of the refractive medium(liquid in this case)
From the information given,
ni = 1(index for air)
θi = 37
θr = 27
By substituting these values into the formula, we have
1 * sin37 = nr * sin27
nr = sin37/sin27
nr = 1.33
The index of the liquid is 1.33
Answer:
Explanation:
A. Using
Sinစ= y/ L = 0.013/2.7= 0.00481
စ=0.28°
B.here we use
Alpha= πsinစa/lambda
= π x (0.0351)sin(0.28)/588E-9m
= 9.1*10^-2rad
C.we use
I(စ)/Im= (sin alpha/alpha) ²
So
{= (sin0.091/0.091)²
= 3*10^-4