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Stolb23 [73]
3 years ago
14

An electromagnetic wave in vacuum has an electric field amplitude of 470 V/m. Calculate the amplitude of the corresponding magne

tic field.
Physics
1 answer:
lapo4ka [179]3 years ago
6 0

Answer:

Magnetic field, B = B=1.56\times 10^{-6}\ T

Explanation:

It is given that,

The amplitude of an electromagnetic wave, E = 470 V/m

We need to find the amplitude of the corresponding magnetic field. The relation between electric and magnetic field is :

B=\dfrac{E}{c}

Where

c is the speed of light

B=\dfrac{470\ V/m}{3\times 10^8\ m/s}

B = 0.00000156

B=1.56\times 10^{-6}\ T

So, the amplitude of the corresponding magnetic field is 1.56\times 10^{-6}\ T. Hence, this is the required solution.

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Explanation:

Given

Heat released by system Q=-255 cal

as heat released is taken as negative and vice-versa

Work done by system W=428 cal

From First law of thermodynamics

Q=\Delta +W , where \Delta U=change in internal Energy

\Delta U=-255-428=-683

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A physics student swings a pail of water in a vertical circle 1.0 m in radius at a constant speed. If the water is NOT to spill
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(A) 3.1 m/s

(B) 2.0 s

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v = 3.1 m/s

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t = 2.0 s

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A produce distributor uses 800 packing crates a month, which it purchases at a cost of $10 each. The manager has assigned an ann
strojnjashka [21]

Answer:

$364.29

Explanation:

given,

Packing of crates per month (u)= 800

annual carrying cost of 35 percent of the purchase price per crate.

Ordering cost(S) = $ 28

D = 800 x 12 = 9600 crates/year

H = 0.35 P

H = 0.35 x $10

H = $3.50/crate per yr.

Present Total cost

= \dfrac{800}{2}\times 3.50 + \dfrac{9600}{800}\times 28

= 1400 + 336

= $ 1,736

Q_0 = \sqrt{\dfrac{2DS}{H}}

Q_0 = \sqrt{\dfrac{2\times 9600 \times 28}{3.50}}

Q_0 =\$ 391.92

Total cost at EOQ

= \dfrac{391.92}{2}\times 3.50 + \dfrac{9600}{391.92}\times 28

= 685.86 + 685.85

= $ 1,371.71

the firm save annually in ordering and carrying costs by using the EOQ

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