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Stolb23 [73]
4 years ago
14

An electromagnetic wave in vacuum has an electric field amplitude of 470 V/m. Calculate the amplitude of the corresponding magne

tic field.
Physics
1 answer:
lapo4ka [179]4 years ago
6 0

Answer:

Magnetic field, B = B=1.56\times 10^{-6}\ T

Explanation:

It is given that,

The amplitude of an electromagnetic wave, E = 470 V/m

We need to find the amplitude of the corresponding magnetic field. The relation between electric and magnetic field is :

B=\dfrac{E}{c}

Where

c is the speed of light

B=\dfrac{470\ V/m}{3\times 10^8\ m/s}

B = 0.00000156

B=1.56\times 10^{-6}\ T

So, the amplitude of the corresponding magnetic field is 1.56\times 10^{-6}\ T. Hence, this is the required solution.

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Air resistance is a force created by air. When an item moves through the air, the force operates in the opposite direction.

When a diver descends, the force of air resistance acts to counteract the force of gravity. As the skydiver falls faster and faster, the quantity of air resistance grows until it equals the magnitude of gravity's force.

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4 0
1 year ago
It is important to wear protective equipment in both practice and games.
Ede4ka [16]

Answer:

OT

It is important to wear protective equipments during games and practices.

Explanation:

Practice is a review of what is about to happen in some time to come and with practice ,the future can be trusted.

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4 0
3 years ago
What term best describes the geologic event taking place in the above illustration?
grigory [225]

u lying you made me get it wrong, for ya'll out there who want the real answer is sea floor spreading

8 0
3 years ago
Read 2 more answers
ANSWER AND I WILL BUY A CAR
Natali [406]
You are exerting 100N. Since there’s no NET force, then there must be exactly 100N pushing exactly back on your 100N to cancel it to exactly zero. Newton's first law states that whether a body is at rest or travelling in a straight line at a constant speed, it will remain at rest or continue to move in a straight line at a constant speed unless acted upon by a force.
8 0
3 years ago
A daring 510-N swimmer dives off a cliff with a running horizontal leap. What must her minimum speed be just as she leaves the t
oee [108]

Answer:

v_x = 1.26 m/s

Explanation:

given,

weight of swimmer = 510 N

length of ledge, L = 1.75 m

vertical height of the cliff, h =  9 m

speed of the swimmer = ?

horizontal velocity  of the swimmer should be that much it can cross the wedge.

distance = speed x time

d = v_x × t

1.75 = v_x × t ........(1)

now,time taken by the swimmer to cover 9 m

initial vertical velocity of the swimmer is zero.

using equation of motion for time calculation

s = ut +\dfrac{1}{2}gt^2

9= 0+\dfrac{1}{2}\times 9.8\times t^2

  t² = 1.938

  t = 1.39 s

same time will be taken to cover horizontal distance.

now, from equation 1

1.75 = v_x × 1.39

v_x = 1.26 m/s

horizontal speed of the swimmer is equal to 1.26 m/s

4 0
3 years ago
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