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Stolb23 [73]
4 years ago
14

An electromagnetic wave in vacuum has an electric field amplitude of 470 V/m. Calculate the amplitude of the corresponding magne

tic field.
Physics
1 answer:
lapo4ka [179]4 years ago
6 0

Answer:

Magnetic field, B = B=1.56\times 10^{-6}\ T

Explanation:

It is given that,

The amplitude of an electromagnetic wave, E = 470 V/m

We need to find the amplitude of the corresponding magnetic field. The relation between electric and magnetic field is :

B=\dfrac{E}{c}

Where

c is the speed of light

B=\dfrac{470\ V/m}{3\times 10^8\ m/s}

B = 0.00000156

B=1.56\times 10^{-6}\ T

So, the amplitude of the corresponding magnetic field is 1.56\times 10^{-6}\ T. Hence, this is the required solution.

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Explain what happens to the sound waves when a singer hits the high pitched notes during the National Anthem. Be sure to use the
Tasya [4]

Answer: The frequency increases as the pitch increases, and the amplitude increases as the volume increases

Explanation:

Waves have the property of:

v = f*λ

where v is the speed of the wave (which is almost constant for soundwaves, v = 340 m/s)

f is the frequency of the wave, and λ is the wavelength.

Now, we know that when the pitch of a note increases, also does the frequency of the soundwave (so the wave oscillates faster).

Now, we also want to include the amplitude of the soundwave in this.

The amplitude is related to the volume of the soundwave (actually is related to the energy, and as higher is the energy, more "loud" is the sound).

As the high pitch part is usually "louder", we can assume that we have an amplitude increase.

Then the answer would be:

"The frequency increases as the pitch increases, and the amplitude increases as the volume increases"

4 0
3 years ago
Uma massa de 500 Kg desloca-se com velocidade 58 km por hora. Calcule o módulo de sua quantidade por movimento
Simora [160]

The momentum of the object is 8050 kg m/s

Explanation:

The momentum of an object is defined as

p=mv

where

p is the momentum

m is the mass

v is the velocity of the object

For the object in this problem, we have

m = 500 kg is its mass

v = 58 km/h is its velocity

Converting the velocity into m/s,

v=58 \frac{km}{h}\cdot \frac{1000 m/km}{3600 s/h}=16.1 m/s

Therefore now we can find the momentum of the object:

p=(500)(16.1)=8050 kg m/s

Learn more about momentum:

brainly.com/question/7973509

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#LearnwithBrainly

7 0
4 years ago
X-rays with an energy of 301 keV undergo Compton scattering with a target. If the scattered X-rays are detected at 77.5^{\circ}
Alex73 [517]

Answer:

6.03\cdot 10^{-12} m

Explanation:

First of all, we need to find the initial wavelength of the photon.

We know that its energy is

E=301 keV = 4.82\cdot 10^{-14}J

So its wavelength is given by:

\lambda = \frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{4.82\cdot 10^{-14} J}=4.13\cdot 10^{-12}m

The formula for the Compton scattering is:

\lambda' = \lambda +\frac{h}{mc}(1-cos \theta)

where

\lambda is the original wavelength

h is the Planck constant

m is the electron mass

c is the speed of light

\theta=77.5^{\circ} is the angle of the scattered photon

Substituting, we find

\lambda' = 4.13\cdot 10^{-12} m +\frac{6.63\cdot 10^{-34} Js)}{(9.11\cdot 10^{-31}kg)(3\cdot 10^8 m/s)}(1-cos 77.5^{\circ})=6.03\cdot 10^{-12} m

7 0
3 years ago
Find change of velocity for:<br> 0-1.7 s<br> 1.7-6s
tekilochka [14]
The integral of acceleration is velocity. The area under the curve is an integral. You can see the relation here. So just take the area under those time intervals. I’m assuming 1.7 is where it crosses the x-axis

For the first interval:
Base = 1.7
Height = -2
[1.7*(-2)]/2 = -1.7 cm/s

For the second interval:
There are two triangles and a rectangle here.
Base #1 = 0.3
Height #1 = 1

Base #2 = 1
Height #2 = 1

Length = 3
Width = 1

Apply the area formulas to get an answer of 3.65 cm/s
3 0
3 years ago
Which of the following statements are correct regarding electric field lines and equipotential lines? (Select all that apply.)
gavmur [86]

Answer:

A)The electric field at a point cannot be in two different directions and therefore two field lines can never cross.

E)If equipotential lines of different potentials cross that would imply that the potential at that point has two different values and that is not physically possible.

Explanation:

A) Field lines cannot be crossed. Otherwise, at the point where the lines cross, there would be two different electric field vectors, which makes no physical sense.

E) Since the electric field is a conservative vector field, it can be defined as the negative value of the gradient of the electric potential, therefore, the same is true as in the previous point.

5 0
3 years ago
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