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rusak2 [61]
3 years ago
6

Decision making worksheet answer key

Physics
1 answer:
mario62 [17]3 years ago
7 0

Answer:

  1. <em><u>do </u></em><em><u>your</u></em><em><u> mom</u></em><em><u> hard</u></em><em><u> to</u></em><em><u> get</u></em><em><u> out</u></em><em><u> of</u></em><em><u> the</u></em><em><u> house</u></em><em><u> </u></em><em><u> you</u></em><em><u> doing</u></em><em><u> today</u></em><em><u> no</u></em><em><u> classes</u></em><em><u> are</u></em><em><u> you</u></em><em><u> doing</u></em><em><u> today</u></em><em><u> no</u></em><em><u> classes</u></em><em><u> are</u></em><em><u> you</u></em><em><u> doing</u></em><em><u> today</u></em><em><u> no</u></em><em><u> classes</u></em><em><u> are</u></em><em><u> not</u></em><em><u> sleeping</u></em><em><u> in</u></em><em><u> my</u></em><em><u> bed</u></em><em><u> you</u></em><em><u> have</u></em><em><u> any</u></em><em><u> best</u></em><em><u> to</u></em><em><u> get</u></em><em><u> the</u></em><em><u> meaning</u></em><em><u> do</u></em><em><u> you</u></em><em><u> want</u></em><em><u> for</u></em><em><u> it</u></em><em><u> is</u></em><em><u> my</u></em><em><u> friend</u></em><em><u> I</u></em><em><u> will</u></em><em><u> be</u></em><em><u> there</u></em><em><u> at</u></em><em><u> 12</u></em><em><u> I</u></em><em><u> have</u></em><em><u> send</u></em><em><u> me</u></em><em><u> a</u></em><em><u> </u></em><em><u>even</u></em><em><u> if</u></em><em><u> </u></em><em><u>we</u></em><em><u> </u></em><em><u>don't</u></em><em><u> ask</u></em><em><u> </u></em><em><u>everyone</u></em><em><u> </u></em><em><u>e</u></em><em><u> for</u></em><em><u> it</u></em><em><u> was</u></em><em><u> a</u></em><em><u> screenshot</u></em><em><u> I</u></em><em><u> am</u></em><em><u> </u></em><em><u>excited</u></em><em><u> </u></em><em><u>everything</u></em><em><u> </u></em><em><u>except</u></em><em><u> you</u></em><em><u> </u></em><em><u>eat</u></em><em><u> your</u></em><em><u> </u></em><em><u>eyes</u></em><em><u> </u></em><em><u>everything</u></em><em><u> </u></em><em><u>except</u></em><em><u> </u></em><em><u>everything</u></em><em><u> else</u></em><em><u> </u></em><em><u>ever</u></em><em><u> </u></em><em><u>even</u></em><em><u> </u></em><em><u>know</u></em><em><u> if</u></em><em><u> </u></em><em><u>everyone</u></em><em><u> e</u></em><em><u> </u></em><em><u>and</u></em><em><u> 10</u></em><em><u> </u></em><em><u>even</u></em><em><u> </u></em><em><u>though</u></em><em><u> it</u></em><em><u> </u></em><em><u>was</u></em><em><u> </u></em><em><u>kiss</u></em><em><u> emoji</u></em><em><u> </u></em><em><u>everything</u></em><em><u> </u></em><em><u>else</u></em><em><u> </u></em><em><u>ever</u></em><em><u> </u></em><em><u>eyebrows</u></em><em><u> </u></em><em><u>yet</u></em><em><u> I</u></em><em><u> </u></em><em><u>eat</u></em><em><u> </u></em><em><u>early</u></em><em><u> </u></em><em><u>to</u></em><em><u> get</u></em><em><u> </u></em><em><u>enough</u></em><em><u> </u></em><em><u>everything</u></em><em><u> </u></em><em><u>except</u></em><em><u> </u></em><em><u>everything</u></em><em><u> is</u></em><em><u> your</u></em><em><u> class</u></em><em><u> finish</u></em><em><u> up</u></em><em><u> </u></em><em><u>early</u></em><em><u> </u></em><em><u>enough</u></em><em><u> </u></em><em><u>even</u></em><em><u> know</u></em><em><u> what</u></em><em><u> is</u></em><em><u> going</u></em><em><u> on</u></em><em><u> with</u></em><em><u> out</u></em><em><u> hajab</u></em><em><u> I</u></em><em><u> have</u></em><em><u> send</u></em><em><u> it</u></em><em><u> out</u></em><em><u> to</u></em><em><u> </u></em><em><u>edit</u></em><em><u> a</u></em><em><u> video</u></em><em><u> on</u></em><em><u> </u></em><em><u>e</u></em><em><u> a</u></em><em><u> video</u></em><em><u> on</u></em><em><u> </u></em><em><u>each</u></em><em><u> </u></em><em><u>e</u></em>

Explanation:

7ün go up to the meaning of the name to the class finish it was in the picture of the meaning is F C B you send me your pic of clans go for a walk and 10 even though I am not say that you wake me up

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A 4.0 kg ball is traveling at 3.0 m/s and strikes a wall. The ball bounces off the wall with a velocity of 4.0 m/s in the opposi
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Answer:

280 N

Explanation:

Applying Newton's third second law of motion,

F = m(v-u)/t................... Equation 1

Where F = Magnitude of the average force on the ball during contact, v = final velocity of the ball, u = initial velocity of the ball, t = time of contact of the ball and the wall.

Note: Let the direction of the initial velocity of the ball be positive

Given: m = 4 kg, u = 3.0 m/s, v = -4.0 m/s (bounce off), t = 0.1 s

Substitute into equation 1

F = 4(-4-3)/0.1

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Note: The negative sign tells that the force on the ball act in opposite direction to the initial motion of the ball

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A 100-W (watt) light bulb has resistance R=143Ω (ohms) when attached to household current, where voltage varies as V=V0sin(2πft)
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Complete Question

A 100-W (watt) light bulb has resistance R=143Ω (ohms) when attached to household current, where voltage varies as V=V0sin(2πft), where V0=110 V, f=60 Hz. The power supplied to the bulb is P=V2R J/s (joules per second) and the total energy expended over a time period [0,T] (in seconds) is U  =  \int\limits^T_0 {P(t)} \, dt

Compute U if the bulb remains on for 5h

Answer:

The value is  U  =  7.563 *10^{5} \  J

Explanation:

From the question we are told that

   The power rating of the bulb is P  =  100 \  W

   The resistance is   R =  143 \ \Omega

   The  voltage is  V  =  V_o  sin [2 \pi ft]

   The  energy expanded is U  =  \int\limits^T_0 {P(t)} \, dt

   The  voltage  V_o  =  110 \  V

   The frequency is  f =  60 \  Hz

    The  time considered is  t =  5 \  h  =  18000 \  s

Generally power is mathematically represented as

             P =  \frac{V^2}{ R}

=>          P =  \frac{( 110  sin [2 \pi * 60t])^2}{ 144}

=>           P =  \frac{ 110^2 [ sin [120 \pi t])^2}{ 144}

So  

     U  =  \int\limits^T_0 { \frac{ 110^2*  [sin [120 \pi t])^2}{ 144}} \, dt

=>  U  =  \frac{110^2}{144} \int\limits^T_0 { (   sin^2 [120 \pi t]} \, dt

=>  U =  \frac{110^2}{144} \int\limits^T_0 { \frac{1 - cos 2 (120\pi t)}{2} } \, dt

=>  U =  \frac{110^2}{144} \int\limits^T_0 { \frac{1 - cos 240 \pi t)}{2} } \, dt

=>  U =  \frac{110^2}{144} [\frac{t}{2}  - [\frac{1}{2} *  \frac{sin(240 \pi t)}{240 \pi} ] ]\left  | T} \atop {0}} \right.

=>  U =  \frac{110^2}{144} [\frac{t}{2}  - [\frac{1}{2} *  \frac{sin(240 \pi t)}{240 \pi} ] ]\left  | 18000} \atop {0}} \right.

U =  \frac{110^2}{144} [\frac{18000}{2}  - [\frac{1}{2} *  \frac{sin(240 \pi (18000))}{240 \pi} ] ]

=>   U  =  7.563 *10^{5} \  J

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