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ollegr [7]
3 years ago
14

Which of the following means "free from all organisms''?

Physics
1 answer:
kati45 [8]3 years ago
3 0

Answer:

4. Sterilization

Explanation:

A reservoir refers to the breeding ground or natural habitat of micro living organisms such as bacterias, fungi, worms, etc. Thus, a reservoir hosts or harbours pathogens and usually serves as a source of infection to other living organisms.

On the other hand, a source of infection refers to a contaminated material from which a disease can be acquired by another living organism.

Pathogen refers to a disease causing organism or substance such as fungi, protozoa, bacteria, virus, etc.

Sterilization simply means to be free from all organisms either pathogenic or nonpathogenic organisms such as spores and viruses.

An autoclave can be defined as a chamber (container) designed to expose an equipment to steam i.e a moisture at high heat and pressure for a specific period of time.

Basically, an autoclave is a container or chamber that is strongly heated and as a result, it is typically used for the sterilization of various laboratory and medical equipments using steam under pressure and high temperature.

This ultimately implies that, an autoclave avails laboratory scientist and other end users the ability to disinfect or sterilize equipments by exposing them to moisture at high heat and pressure for a specific period of time.

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Match the correct sentence together.
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I’m pretty sure you times them so 1 with A, 2 with e, 3 with C, and 4 with B
6 0
2 years ago
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A student heats a piece of aluminum, with specific heat 0.900 J/gºC, in
tankabanditka [31]

Answer:

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Explanation:

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8 0
3 years ago
A positively charged object is brought near but not in contact with the top of an uncharged gold leaf electroscope. The experime
Olin [163]

Answer:

The leaves of the electroscope move further apart.

Explanation:

This is what happens; when the positive object is brought near the top, negative charges migrating from the gold leaves to the top. This is because the negative charges in the gold are attracted by the positive charge. Thus, it leaves behind a net positive charge on the leaves, though the scope remains neutral overall. To that effect, the leaves repel each other and move apart. If a finger touches the top of the electroscope at the moment when the positive object remains near the top, it basically grounds the electroscope and thus the net positive charge in the leaves flows to the ground through the finger. However, the positive object continues to "hold" negative charges in place at the top. Ar this moment the gold leaves have lost their net positive charge, so they no longer repel, and they move closer together. If the positive object is moved away, the negative charges at the top are no longer attracted to the top, and they redistribute themselves throughout the electroscope, moving into the leaves and charging them negatively.

Thus, the leaves move apart from each other again and we now have a negatively charged electroscope. If a negatively charged object is now brought close to the top, but without touching, the negative charges already in the electroscope will be repelled down toward the leaves, thereby making them more negative, causing them to repel more, and hence move even further apart.

So, the leaves move further apart.

7 0
3 years ago
If we double the frequency of a system undergoing simple harmonic motion, which of the following statements about that system ar
AnnyKZ [126]

Answer:

a. The angular frequency is doubled.

e. The period is reduced to one-half of what it was.

Explanation:

Angular frequency is given as;

ω = 2πf

\frac{\omega _1}{f_1} = \frac{\omega _2}{f_2}

when the frequency is doubled

\frac{\omega _1}{f_1} = \frac{\omega _2}{(2f_1)} \\\\\omega _1 = \frac{\omega _2}{2}\\\\\omega _2 = 2\omega _1

Thus, the angular frequency will be doubled.

Amplitude in simple harmonic motion is the maximum displacement.

Frequency is related to period in simple harmonic motion as given in the equation below;

f = \frac{1}{T} \\\\f_1T_1= f_2T_2\\\\T_2 = \frac{f_1T_1}{f_2}

when the frequency is doubled;

T_2 = \frac{f_1T_1}{2f_1} \\\\T_2 = \frac{T_1}{2}

Thus, the period will be reduced to one-half of what it was.

5 0
3 years ago
R1=3 ohms
brilliants [131]

Answer: current I = 1.875A

Explanation:

If the resistors are connected in series,

Then the equivalent resistance will be

R = 6 + 18 + 15 + 9

R = 48 ohms

Using ohms law

V = IR

Make current I the subject of formula

I = V/R

I = 90/48

I = 1.875A

And if the resistors are connected in parallel, the equivalent resistance will be

1/R = 1/6 + 1/18 + 1/15 + 1/9

1/R = 0.166 + 0.055 + 0.066 + 0.111

R = 1/0.3999

R = 2.5 ohms

Using ohms law

V = IR

I = 90/2.5

Current I = 35.99A

3 0
3 years ago
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