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ollegr [7]
2 years ago
14

Which of the following means "free from all organisms''?

Physics
1 answer:
kati45 [8]2 years ago
3 0

Answer:

4. Sterilization

Explanation:

A reservoir refers to the breeding ground or natural habitat of micro living organisms such as bacterias, fungi, worms, etc. Thus, a reservoir hosts or harbours pathogens and usually serves as a source of infection to other living organisms.

On the other hand, a source of infection refers to a contaminated material from which a disease can be acquired by another living organism.

Pathogen refers to a disease causing organism or substance such as fungi, protozoa, bacteria, virus, etc.

Sterilization simply means to be free from all organisms either pathogenic or nonpathogenic organisms such as spores and viruses.

An autoclave can be defined as a chamber (container) designed to expose an equipment to steam i.e a moisture at high heat and pressure for a specific period of time.

Basically, an autoclave is a container or chamber that is strongly heated and as a result, it is typically used for the sterilization of various laboratory and medical equipments using steam under pressure and high temperature.

This ultimately implies that, an autoclave avails laboratory scientist and other end users the ability to disinfect or sterilize equipments by exposing them to moisture at high heat and pressure for a specific period of time.

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Answer:

C Or D

Explanation:

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An insulated pipe carries steam at 300°C. The pipe is made of stainless steel (with k = 15 W/mK), has an inner diameter is 4 cm,
insens350 [35]

Answer:

The answers to the question are

(i) The rate of heat loss per-unit-length (W/m) from the pipe is 131.62 W

(ii) The temperature of the outer surface of the insulation is 49.89 °C

Explanation:

To solve the question, we note that the heat transferred is given by

Q = \frac{2\pi L(t_{hf} - t_{cf}) }{\frac{1}{h_{hf}r_1}+\frac{ln(r_2/r_1)}{k_A} + \frac{ln(r_3/r_2)}{k_B} +\frac{1}{h_{cf}r_3}}

Where

t_{hf} = Temperature at the inside of the pipe = 300 °C

t_{f} = Temperature at the outside of the pipe = 20 °C

r₁ =internal  radius of pipe = 4.0 cm

r₂ = Outer radius of pipe = 4.5 cm

r₃ = Outer radius of the insulation = r₂ + 2.5 = 7.0 cm

k_A = 15 W/m·K

k_B = 0.038 W/m·K

h_{hf} = 75 W/m²·K

h_{cf} = 10 W/m²·K

Plugging in the values in the above equation where for a unit length L = 1 m, we have

Q = 131.32 W

From which we have, for the film of air at the pipe outer boundary layer

Q = \frac{t_A-t_B}{R_T} Where R_T for the air film on the pipe outer surface is given by

R_T= \frac{1}{\alpha A}

where A =area of the outside of the pipe

= \frac{1}{10*2\pi*0.07*1 } = 0.227 K/W

Therefore

131.32 W = \frac{t_A-20}{0.227} which gives

t_A = 49.89 °C

Heat transferred by radiation = q' = ε×σ×(T₁⁴ - T₂⁴)

Where ε = 0.9, σ, = 5.67×10⁻⁸W/m²·(K⁴)

T₁ = Surface temperature of the pipe = 49.89 °C and

T₂ = Temperature of the surrounding = 20.00 °C

Plugging in the values gives, q' = 0.307 W per m²

Total heat lost per unit length = 131.32 + 0.307 =131.62 W

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