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sineoko [7]
2 years ago
15

A 2kg ball rotates on the end of a 1.4m long string. The ball makes 5 revolutions in 4.4s. What is the speed of the ball?

Physics
1 answer:
nlexa [21]2 years ago
3 0

The speed or the linear velocity of the stone is 9.93 m/s; option C

<h3>What is the speed or linear velocity of the stone?</h3>

The linear velocity of the stone is given by the formula below:

  • v = wr

where w is angular velocity and r is radius.

w = θ/t

1 complete revolution = 2π radians

5 revolutions = 10π radians

w =  10π/4.4 rad/s

v = 10π/4.4 rad/s * 1.4

v = 9.93 m/s

In conclusion, the linear velocity is obtained from the angular velocity and radius of the string.

Learn more about linear and angular velocity at: brainly.com/question/15154527

#SPJ1

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Inertia is ______ to mass.
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Answer:

Inertia is directly proportional to mass of an object. Therefore, when the force of inertia increases the mass also increases, and when it decreases the mass also decreases.

Explanation:

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Someone please help me, I’m so lost my brain hurts
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-- It takes 100 calories of heat to make 10 grams of the stuff 20° warmer.

How much of the heat warms each gram ?

-- It takes 10 calories of heat to make each gram of the stuff 20° warmer.

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-- It takes 1/2 calorie of heat to make each gram of the stuff 1° warmer.

The specific heat of that stuff is

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The temperature of the cooling water as it leaves the hot engine of an automobile is 240 °F. After it passes through the radiato
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Answer:571.09 kJ

Explanation:

Given

Temperature of cooling water from engine exit=240^{\circ} F\approx 115.55^{\circ}C

After Passing through the radiator its temperature decreases to 175^{\circ}F\approx 79.44^{\circ}F

specific heat of water=4.184 J/g^{\circ}C

Volume of water = 1 gallon\approx 3.78 L

density of water \rho =1 gm/mL

Thus mass of water=\rho \times V=3.78\times 1=3.78 kg

Heat transferred to the surrounding is equal to heat absorbed by cooling water

Q=m\cdot c\cdot \Delta T

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4 0
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ILI
Nikolay [14]

The original kinetic energy will be 0 J and the final kinetic energy will be 7500 J and the amount of work utilized will be similar to the final kinetic energy i.e., 7500 J.

<u>Explanation:</u>

As it is known that the kinetic energy is defined as the energy exhibited by the moving objects. So the kinetic energy is equal to the product of mass and square of the velocity attained by the car. Thus,

                  \text {Kinetic energy}=\frac{1}{2} m v^{2}

So the initial kinetic energy will be the energy exerted by the car at the initial state when the initial velocity is zero. Thus the initial kinetic energy will be zero.  

The final kinetic energy is

\text {Kinetic energy}=\frac{1}{2} m v^{2}=\frac{1}{2} \times 600 \times 5 \times 5 = 7500 J

As the work done is the energy required to start the car from zero velocity to 5 m/s velocity.  

                       Work done = Final Kinetic energy - Initial Kinetic energy

Thus the work utilized for moving the car is  

                         Work done = 7500 J - 0 J = 7500 J

Thus, the initial kinetic energy of the car is zero, the final kinetic energy is 7500 J and the work utilized by the car is also 7500 J.

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Answer:

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