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sineoko [7]
2 years ago
15

A 2kg ball rotates on the end of a 1.4m long string. The ball makes 5 revolutions in 4.4s. What is the speed of the ball?

Physics
1 answer:
nlexa [21]2 years ago
3 0

The speed or the linear velocity of the stone is 9.93 m/s; option C

<h3>What is the speed or linear velocity of the stone?</h3>

The linear velocity of the stone is given by the formula below:

  • v = wr

where w is angular velocity and r is radius.

w = θ/t

1 complete revolution = 2π radians

5 revolutions = 10π radians

w =  10π/4.4 rad/s

v = 10π/4.4 rad/s * 1.4

v = 9.93 m/s

In conclusion, the linear velocity is obtained from the angular velocity and radius of the string.

Learn more about linear and angular velocity at: brainly.com/question/15154527

#SPJ1

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The tangential acceleration of a cart moving at a constant speed in a horizontal circle is:
qaws [65]

Answer:

a=0                                  ∵ \alpha=0\ rad.s^{-1}

Explanation:

The tangential acceleration of a cart moving at a constant speed in a circle is:

The angular velocity is constant when the circular speed is constant.

We know that the (instantaneous) tangential velocity of such object is given by:

v=r.\omega

Now for angular acceleration we have a constant angular speed:

\alpha=0\ rad.s^{-1}

And angular acceleration is related to tangential acceleration as:

a=r.\alpha

\Rightarrow a=0

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Suppose a 48-N sled is resting on packed snow. The coefficient of kinetic friction is 0.10. If a person weighing 660 N sits on t
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Assume the snow is uniform, and horizontal.

Given:

coefficient of kinetic friction = 0.10 = muK

weight of sled = 48 N

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normal force on of sled with rider = 48+660 N = 708 N = N

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