Answer: 9.55 moles
Explanation: Moles are the base unit of atoms, molecules, ions, or any other substance. It is exactly 6.022 × 10²³ entities of any substance. The mole is equal to the ratio of the given mass to the molar mass.
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In NaMnO₄, Mn has the highest oxidation number.
The question is incomplete, the complete question is;
Which of the following species contains manganese with the highest oxidation number?
A) Mn
B) MnF₂
C) Mn₃(PO₄)₂
D) MnCl₄
E) NaMnO₄
In order to ascertain the specie that contains manganese with the highest oxidation number, we must calculate the oxidation number of manganese in each of the species one after the other.
1) For Mn, the oxidation number of Mn is zero because the atom is uncombined.
2) For MnF₂;
Mn has an oxidation number of +2
3) For Mn₃(PO₄)₂
Mn has an oxidation number of +2
4) For MnCl₄
Mn has an oxidation number of +4
5) For NaMnO₄
Mn has an oxidation number of +7
Hence in NaMnO₄, Mn has the highest oxidation number.
Learn more: brainly.com/question/10079361
The given equation is is
this is not balanced
The balanced equation will be:
Now as per it if we are using eight moles of HNO3 we are getting two moles of NO
so for each mole of NO we have to take four moles of HNO3
Hence the mole ratio of NO produced to HNO3 reacted will be = 1:4
