All categories

3 years ago

Calculate the number of moles in 23.8 grams of Nitrogen, N.

Chemistry

1 answer:

Vlad1618 [11]3 years ago

8 0

Answer:

n = 1.7 moles

Explanation:

Given mass, m = 23.8 grams

Molar mass of Nitrogen = 14 g/mol

Let there is n number of moles. We know that,

No. of moles = given mass/ molar mass

$n=\dfrac{23.8}{14}\\\\n=1.7$

So, there are 1.7 moles in 23.8 grams of Nitrogen.

You might be interested in

Five solutions on how to prevent air pollution

I am Lyosha [343]

Answer:

Reduce number of trips

Avoid burning leaves

Avoid using garden equipments

Reduce the use of wood stove

Avoid gas-powered lawn.

Explanation:

7 0

3 years ago

Magnesium and copper react with dilute acids to make salts and hydrogen gas<br> True<br> False

omeli [17]

Answer:

True

Explanation:

magnesium and copper react with dilute acids to make salts and hydrogen gas

5 0

3 years ago

noble gases are used in many situations where a safe and constant environment must be maintained. for example, helium is used to

Lapatulllka [165]

Answer:

Noble gases have a complete valence electron shell making them stable and nonreactive.

Explanation:

4 0

2 years ago

What is the Ka of a weak acid (HA) if the initial concentration of weak acid is 4.5 x 10-4 M and the pH is 6.87? (pick one)

rewona [7]

Answer:

Ka = $4.04 \times 10^{-11}$

Explanation:

Initial concentration of weak acid = $4.5 \times 10^{-4}\ M$

pH = 6.87

$pH = -log[H^+]$

$[H^+]=10^{-pH}$

$[H^+]=10^{-6.87}=1.35 \times 10^{-7}\ M$

HA dissociated as:

$HA \leftrightharpoons H^+ + A^{-}$

(0.00045 - x) x x

[HA] at equilibrium = (0.00045 - x) M

x = $1.35 \times 10^{-7}\ M$

$Ka = \frac{[H^+][A^{-}]}{[HA]}$

$Ka = \frac{(1.35 \times 10^{-7})^2}{0.00045 - 0.000000135}$

0.000000135 <<< 0.00045

$Therefore, Ka = \frac{(1.35 \times 10^{-7})^2}{0.00045 } = 4.04 \times 10^{-11}$

5 0

3 years ago

What is the missing value

Korvikt [17]

Answer:

Explanation:

The pattern here may be hard to find at first, but it's this: the number in the middle of the triangle = (number at lower left corner of triangle x number at upper vertex of triangle) + (number at upper vertex of triangle x number at lower right corner of triangle).

Thus, for the missing value...

Missing value = (3x8) + (8x6) = 24+48 = 72.

Could you tell me what concept in chemistry relates to this? I'm interested.

Also check out stylesben's answer. Seems like there's several ways of doing this.

7 0

2 years ago

Read 2 more answers