Answer:
Coins weigh less on the Moon.
Explanation:
Gravity is only 1/6th as strong on the Moon than it is on Earth. Where a nickle is about 5 grams on Earth, it is less than 1 gram on the Moon. Gravity is affected by the size of the planet or moon. The Moon is much less massive than the Earth.
Answer:
The detailed explanation of answer is given in attached file.
Explanation:
<h2>
˜”*°•.˜”*°• Question •°*”˜.•°*”˜
</h2>
<em>What Member function places a new node at the end of the linked list?
</em>
<h2>
˜”*°•.˜”*°• Answer •°*”˜.•°*”˜</h2>
appendNode
<h2>˜”*°•.˜”*°• Explanation •°*”˜.•°*”˜</h2>
The appendNode() member function places a new node at the end of the linked list. The appendNode() requires an integer representing the current data of the node.
<h2>˜”*°•.˜”*°• Details •°*”˜.•°*”˜</h2>
Subject: Coding (?)
Grade: College
Keywords: Function, linked list, appendNode, integer
Hope this helped. <3
Answer:
W = 112 lb
Explanation:
Given:
- δb = 0.025 in
- E = 29000 ksi (A-36)
- Area A_de = 0.002 in^2
Find:
Compute Weight W attached at C
Solution:
- Use proportion to determine δd:
δd/5 = δb/3
δd = (5/3) * 0.025
δd = 0.0417 in
- Compute εde i.e strain in DE:
εde = δd / Lde
εde = 0.0417 / 3*12
εde = 0.00116
- Compute stress in DE, σde:
σde = E*εde
σde = 29000*0.00116
σde = 33.56 ksi
- Compute the Force F_de:
F_de = σde *A_de
F_de = 33.56*0.002
F_de = 0.0672 kips
- Equilibrium conditions apply:
(M)_a = 0
3*W - 5*F_de = 0
W = (5/3)*F_de
W = (5/3)* 0.0672 = 112 lb
I want say the best answer is C a sister-in-law Tran