Answer:
Please check the explanation.
Explanation:
While driving, white lines would require us to stay within the lane, also marking the shoulder of the roadway.
While yellow lines generally mark the center of a two-way road being used for two-way traffic.
We generally can pass on a two-way road if the yellow centerline is broken.
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Answer:
16 seconds
Explanation:
Given:
C = 60
L = 4 seconds each = 4*4 =16
In this problem, the first 3 timing stages are given as:
200, 187, and 210 veh/h.
We are to find the estimated effective green time of the fourth timing stage. The formula for the estimated effective green time is:
Let's first find the fourth stage critical lane group ratio 
, using the formula:
Solving for 
, we have:
Let's also calculate the volume capacity ratio X,
X = 0.704
For the the estimated effective green time of the fourth timing stage, we have:
Substituting figures in the equation, we now have:
15.78 ≈ 16 seconds
The estimated effective green time of the fourth timing stage is 16 seconds
Answer:
Explanation:
R1 = 1 k; R2 = 1k; R3 = 3k; R4 = 6k; R5 = 5k; R6 = 6k and R7 = 2k
Vt = 428V
The series and parallel circuit combination is as follow:
(R6║R7 + R5) + R4 + R3║R2 + R1
(6*2/6 + 2) + 5 = 13/ k
(13/2*6/13/6 + 6) = 78/31k
78/3 + 3 = 171/3 = 57k
57k║R2 = 57k║1k = 57/58k + R1 = (57/58 + 1)k = 115/58k = 2k
It = Vt/2k = 428/2000 = 0.2A
∴ I1 = 0.2A
I1 = I2 + I3
Using current divider rules to obtain I2 and I3
∴ I2 = I1 X (I2/I2 + I3) = 0.2 X ( 1/4) = 0.05A
and I3 = I1 X (I3/I2 + I3) = 0.2 X (3/4) = 0.15A
I3 = I4 + I5, using current divider
I4 = I3 X (I4/I4 + I5) = 0.15 X (6/6 + 5) = 0.08
I5 = 0.15 - 0.08 = 0.07A
I5 = I6 + I7, using current divider
I6 = I5 X (I6/I6 + I7) = 0.07 X (6/6 + 2) = 0.05A
I7 = 0.07 - 0.05 = 0.02A
