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GREYUIT [131]
4 years ago
13

How does Mercury's close proximity to the sun and thin atmosphere affect its ability to maintain liquid water

Physics
1 answer:
alekssr [168]4 years ago
5 0

Answer

A thin atmosphere does not supply much oxygen, and the heat from the sun would evaporate it, because mercury is close to the sun.

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In nature, where do fusion reactions take place?
hjlf
Fusion reactions happen in stars 
3 0
3 years ago
Read 2 more answers
Which of the following diagrams shows the path of deep water currents in the ocean?
Whitepunk [10]
I hope this helps. ^-^

6 0
3 years ago
A mass hanging from a spring oscillates with a period of 0.35 s. Suppose the mass and spring are swung in a horizontal circle, w
Annette [7]

Answer:

66 rpm

Explanation:

The period of oscillation is given by

T=2\pi \sqrt{\frac {m}{k}}

\frac {k}{m}=\frac {4\pi^{2}}{T^{2}} where  T is time period of oscillation which is given as 0.35 s, k s spring constant and m is the mass of the object attached to the spring.

Also, net force is given by

Net force=m\omega^{2} L

\omega=\sqrt{\frac {k\triangle L}{mL}} where \triangle L is the elongation, L is original length, \omega is the angular velocity

Substituting the equation of \frac {k}{m} into the above we obtain

\omega=\sqrt {\frac {4\pi^{2}\triangle L}{T^{2} L}}

\omega=\sqrt {4\pi^{2}\times 0.15L}{0.35^{2}\times L}}=6.952763\approx 6.95 rad/s

6.95\times\frac {60 s}{2\pi rad}\approx 66 rpm

6 0
3 years ago
Light reflected from a glass surface is polarized along the plane perpendicular to the glass surface. Please select the best ans
leva [86]

I believe it would be true not 100% sure


7 0
3 years ago
A 10.00-kilogram block slides along a horizontal, frictionless surface at 12.0 meters per second for 6.00 seconds. The magnitude
earnstyle [38]

Answer:

120 kg m/s

Explanation:

The magnitude of the momentum of an object is given by

p=mv

where

m is the mass of the object

v is its speed

For the block in this problem,

m = 10.0 kg (mass of the block)

v = 12.0 m/s (speed of the block)

Therefore the magnitude of the block's momentum is

p=(10.0 kg)(12.0 m/s)=120 kg m/s

4 0
3 years ago
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